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kiruha [24]
3 years ago
8

What is its maximum altitude above the ground? The answer is the maximum height above the ground

Physics
1 answer:
Kisachek [45]3 years ago
3 0

Answer:

Maximum altitude above the ground = 1,540,224 m = 1540.2 km

Explanation:

Using the equations of motion

u = initial velocity of the projectile = 5.5 km/s = 5500 m/s

v = final velocity of the projectile at maximum height reached = 0 m/s

g = acceleration due to gravity = (GM/R²) (from the gravitational law)

g = (6.674 × 10⁻¹¹ × 5.97 × 10²⁴)/(6370000²)

g = -9.82 m/s² (minus because of the direction in which it is directed)

y = vertical distance covered by the projectile = ?

v² = u² + 2gy

0² = 5500² + 2(-9.82)(y)

19.64y = 5500²

y = 1,540,224 m = 1540.2 km

Hope this Helps!!!

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The equatorial diameter of earth is 7928 miles. If a mile equals 1.609 km, what is the earth's diameter in kilometers? in centim
tangare [24]

diameter of earth in miles= 7928 miles

1 mile = 1.609 km

diameter of earth in km= 7928*1.609

                                         =12,756.152 km

Hope it helped u, pls thank if u find this helpful

and don't forget to put this answer as the brainliest.

^_^.

7 0
3 years ago
Suppose we have a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it trie
sammy [17]

Answer:

2.64 m/s

Explanation:

Given that a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna

Momentum = MV

Momentum of the yellow shark before collision = 600 × 3 = 1800 kgm/s

Momentum of the tun final before collision = 100 × 0.5 = 50 kgm/s

Total momentum before collision = 1800 + 50 = 1850 kgm/s

Let's assume that they move together after collision. Then,

1850 = ( 600 + 100 ) V

1850 = 700V

V = 1850 / 700

V = 2.64285 m/s

Therefore, the momentum of the shark after collision is 2.64 m/ s approximately

6 0
3 years ago
A basket has a mass of 5.5 kg. Find the magnitude of the normal force if the basket is at rest on a ramp inclined above the hori
storchak [24]
Here is the correct answer of the given problem above.
Given that the basket has a mass of 5.5kg, the magnitude of the normal force if the basket is at rest on a ramp inclined above the horizontal is at 12 degrees. The solution is simple: 
<span>Fn at rest = lmgl </span>
<span>= 5.5kg (9.80N/kg) 
=</span><span> mgCos12degrees 
Hope this answer helps. </span>
8 0
3 years ago
Read 2 more answers
A very long train is rolling at 4 m/s along a straight track. An observer is standing on the ground very dangerously close to th
hichkok12 [17]

Answer:

A. \vec{r}=(6\frac{m}{s})t\ \ \hat{i}

B.  t = 50 s

Explanation:

A. The vectorial equation of the person who is getting closer to the other person is:

\vec{r}=\vec{v}t

r: position vector

v: speed vector = 6m/s i  (if you consider the motion as a horizontal motion)

Then, you replace and obtain:

\vec{r}=(6\frac{m}{s})t\ \ \hat{i}

B. The time is:

t=\frac{d}{v}

d: distance to the observer = 300m

v: speed of the person on the car = 6.00 m/s

t=\frac{300m}{6m/s}=50s

4 0
3 years ago
A tank of gasoline (n = 1.40) is open to the air (n = 1.00). A thin film of liquid floats on the gasoline and has a refractive i
klio [65]

Answer:

1.08

Explanation:

This is the case of interference in thin films in which interference bands are formed due to constructive interference of two reflected light waves , one from upper layer and the other from lower layer . If t be the thickness and μ be the refractive index then

path difference created will be 2μ t.

For light coming from rarer to denser medium , a phase change of π occurs additionally after reflection from denser medium, here, two times, once from upper layer and then from the lower layer ,  so for constructive interference

path diff = nλ , for minimum t , n =1

path diff = λ

2μ t. =  λ

μ = λ / 2t

= 626 / 2 x 290

= 1.08

5 0
3 years ago
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