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attashe74 [19]
3 years ago
6

A person pushes horizontally with a force of 220. N on a 61.0 kg crate to move it across a level floor. The coefficient of kinet

ic friction is 0.270. (a) What is the magnitude of the frictional force? (b) What is the magnitude of the crate's acceleration? Use g=9.81 m/s2.
Physics
1 answer:
Ede4ka [16]3 years ago
7 0

Answer:

(a) 161.57 N

(b) 0.958 m/s^2

Explanation:

Force applied, F = 220 N

mass of crate, m = 61 kg

μ = 0.27

(a) The magnitude of the frictional force,

f = μ N

where, N is the normal reaction

N = m x g = 61 x 9.81 = 598.41 N

So, the frictional force, f = 0.27 x 598.41

f = 161.57 N

(b) Let a be the acceleration of the crate.

Fnet = F - f = 220 - 161.57

Fnet = 58.43 N

According to newton's second law

Fnet = mass x acceleration

58.43 = 61 x a

a = 0.958 m/s^2

Thus, the acceleration of the crate is 0.958 m/s^2.  

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Conservation of momentum.

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Explanation:

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Acceleration = (70 / 2.5) m/s²

<em>Acceleration = 28 m/s²</em>  

That's about 2.9 G's .  Jet pilots can endure a lot more than that, but maybe the catapult or the hook on the airplane can't.  Let's look a little closer:

F = m A (Newton #2)

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Also, the REACTION force on the catapult is the same 113,000 pounds.  Maybe the hooks or the chains or the struts on the catapult can't handle any more force than that.

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8 0
3 years ago
How many neutrons does element X have if it’s atomic number is 28 and it’s mass number is 81?
labwork [276]

Well let’s put it this way. To find the neutrons you subtract the atomic atomic Nuremberg from the atomic mass. So

Mass=81-Number=28

81-28=53

Final answer is 53.

5 0
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A steel wire in a piano has a length of 0.680 m and a mass of 4.600 ✕ 10⁻³ kg. To what tension must this wire be stretched so th
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Answer:

728 N

Explanation:

L = length of the wire = 0.680 m

m = mass of the steel wire = 0.0046 kg

f = Fundamental frequency = 261.6 Hz

T = tension force in the steel wire

Fundamental frequency in wire is given as

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