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3 years ago

What volume of concentrated nitric acid (15.0M) is requiredfor

Chemistry

1 answer:

seraphim [82]3 years ago

5 0

Answer:

0.133 mL

Explanation:

Given data

Initial concentration (C₁): 15.0 M

Initial volume (V₁): to be determined

Final concentration (C₂): 0.001 M

Final volume (V₂): 2.00 L

We can find the volume of the concentrated solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.001 M × 2.00 L / 15.0 M

V₁ = 1.33 × 10⁻⁴ L = 0.133 mL

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3 years ago

Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O

Kipish [7]

Answer:

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

Explanation:

Moles of NaOH = $\frac{15.0 g}{40 g/mol}=0.375 mol$

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Volume of the nitric solution = 0.150 L

Moles of nitric acid = n

$Molarity=\frac{Moles}{Volume(L)}$

$n=0.250 M\times 0.150 L=0.0375 mol$

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According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :

$\frac{1}{1}\times 0.0375 mol$ of NaOH

Moles of NaOH left unreacted in the solution =

= 0.375 mol - 0.0375 mol = 0.3375 mol

$NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)$

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.

Then 0.3375 moles of NaOH will give :

$1\times 0.3375 moles=0.3375 mol$ of hydroxide ion

The molarity of hydroxide ion in solution ;

$=\frac{0.3375 mol}{0.150 L}=2.25 M$

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

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3 years ago

If there is a 2 kg ball with the same kinetic energy which one will be moving faster

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Answer:

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Explanation:

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3 years ago

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3 years ago

.325 mol KOH to grams

lesya [120]

The answer is 18.23432 grams.

Molar mass of KOH= 56.1056

$( \frac{1 mol}{56.1056 grams}) (\frac{.325 mol}{x grams})$ = 18.234 grams

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3 years ago