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kow [346]
2 years ago
12

What volume of concentrated nitric acid (15.0M) is requiredfor

Chemistry
1 answer:
seraphim [82]2 years ago
5 0

Answer:

0.133 mL

Explanation:

Given data

  • Initial concentration (C₁): 15.0 M
  • Initial volume (V₁): to be determined
  • Final concentration (C₂): 0.001 M
  • Final volume (V₂): 2.00 L

We can find the volume of the concentrated solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.001 M × 2.00 L / 15.0 M

V₁ = 1.33 × 10⁻⁴ L = 0.133 mL

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Uranium-267 undergoes alpha decay, what is the mass of the new element?
Firlakuza [10]

Answer:

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Explanation:

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3 0
2 years ago
What can you say about the strength of the intermolecular forces in neon and argon based on the critical points of Ne and Ar? (c
algol13

Explanation:

Since, it is given that critical temperature of Argon is 150.9 K and critical pressure of Argon is 48.0 atm.

It is known that gas phase of neon occurs at 50 K. As the boiling point of Ar is more than the boiling point of neon which means that there is strong intermolecular force of attraction between argon molecules as compared to neon molecules.

This is also because argon is larger in size. As a result, induced dipole-induced dipole forces leads to more strength in Ar as compared to Ne.

8 0
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How many moles of oxygen gas are there in 395 L of oxygen at STP?
kozerog [31]

Answer:

17.6 moles of oxygen gas.

Explanation:

STP Variables:

P=1 atm

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Use the PV=nRT, then plug in.

n=PV/RT

n= (1 atm)(395 L)/(0.082) (273 K)

Simplify.

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Hoped this helped.

7 0
2 years ago
(?) NH4NO3 ---> (?) N2O + (?) H2O
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Answer:

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Explanation:

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