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son4ous [18]
3 years ago
13

. Explain why, in the sample calculations, 0.1 g of the unknown produced a GREATER freezing point depression than~e same mass of

naphthalene.
Chemistry
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer

Naphthalene is a non electrolyte

If the unknown compound is an electrolyte it gives 2 or more ions in solution

( NaCl >> Na+ + Cl- => 2 ions

Ca(NO3)2 >> Ca2+ + 2 NO3- => 3 ions)

the f.p. lowering is directly proportional to the molal concentration of dissolved ions in the solution )

For naphthalene

delta T = 1.86 x m

for a salt that gives 2 ions

delta T = 1.86 x m x 2

hence the lowering in freezion point of unkown is greater then napthalene

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Potassium permanganate, KMnO, and glycerin, C3H5(OH)3, react explosively according to the
Finger [1]

The volume of CO2 at STP =124.298 L

<h3>Further explanation</h3>

Given

Reaction

4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O

701,52 g of KMnO4

Required

volume of CO2 at STP

Solution

mol KMnO4 (MW=158,034 g/mol) :

mol = mass : MW

mol = 701.52 : 158.034

mol = 4.439

mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549

At STP 1 mol = 22.4 L, so for 5.549 moles :

=5.549 x 22.4

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4 0
3 years ago
How do you determine the proper number of significant figures of a liquid using a graduated cylinder
Aleksandr [31]
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4 0
3 years ago
What information does Jaime need to evaluate the accuracy of his calculation?
Effectus [21]

Answer:

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4 0
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Rzqust [24]

Answer:

Explanation:

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5 0
3 years ago
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So,

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where n is the number of each atom present.

(12 +1)n = 78

n = 78/13

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The molecular formula of the compound is C6H6

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brainly.com/question/24305135

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