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son4ous [18]
3 years ago
13

. Explain why, in the sample calculations, 0.1 g of the unknown produced a GREATER freezing point depression than~e same mass of

naphthalene.
Chemistry
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer

Naphthalene is a non electrolyte

If the unknown compound is an electrolyte it gives 2 or more ions in solution

( NaCl >> Na+ + Cl- => 2 ions

Ca(NO3)2 >> Ca2+ + 2 NO3- => 3 ions)

the f.p. lowering is directly proportional to the molal concentration of dissolved ions in the solution )

For naphthalene

delta T = 1.86 x m

for a salt that gives 2 ions

delta T = 1.86 x m x 2

hence the lowering in freezion point of unkown is greater then napthalene

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20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volu
belka [17]
10 cubic inches
We will use Boyle's law that states that for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. 
P1 V1 = P2 V2
Where
 P1 is initial pressure = 5 psi
V1 is initial volume = 20 cubic inch
P2 is final pressure = 10 psi
V2 is final volume = unknown
V2 = P1,V1 / P2
V2 = 20 × 5 / 10
V2 = 100/10
V2 = 10 cubic inches


7 0
3 years ago
The 500kg concrete culvert has a mean radius of 0.5m. part a if the truck has an acceleration of 3m/s2, determine the culvert's
jarptica [38.1K]

<u>Given: </u>

Radius of culvert, r = 0.5 m

Tangential acceleration of the truck, a = 3 m/s2

<u>To determine:</u>

The angular acceleration, α

<u>Explanation:</u>

The tangential acceleration is related to the angular acceleration through the radius as:

a = rα

α = a/r = 3 ms⁻²/0.5 m = 6 s⁻²

Ans: The angular acceleration is 6 s⁻²


6 0
3 years ago
The diameter of a carbon atom is 0.000000000154 m. What is this number expressed in scientific notation?
Viktor [21]
1.54 x 10^-10 (ten to the negative tenth power)
8 0
3 years ago
Read 2 more answers
Help, please!
professor190 [17]

Hi so from what I can see the pizza as a distant or and you just have to convert the grams of glucose into moles. Most teachers ask for this format

7 0
3 years ago
Complete combustion of 3.20g of a hydrocarbon produced 9.69g of CO2 and 4.96g of H2O. What is the empirical formula for the hydr
vlabodo [156]

Let empirical formula for hydrocarbon is CxHy

it will undergo combustion as

CxHy + (x + y/4) O2  ---> xCO2 + (y/2 )H2O

Given that mass of CO2 produced = 9.69 g

So moles of CO2 produced = 9.69 / 44 = 0.22 moles

So moles of carbon present = 0.22 moles

mass of H2O produced = 4.96 g

Moles of H2O produced = mass / molar mass = 4.96 / 18 = 0.28 moles

So moles of H present = 2 X 0.28 = 0.56 moles

Let us divided the moles of each with lowest value of moles

Moles of Carbon = 0.22 / 0.22 = 1 moles

moles of H = 0.56 / 0.22 = 2.55

Multiplying with two to get whole number

the ratio of carbon and hydrogen will be : C:H = 2:5

empirical formula : C2H5


4 0
3 years ago
Read 2 more answers
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