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spayn [35]
3 years ago
14

Why will frequency decrease when wave gets longer

Chemistry
1 answer:
amid [387]3 years ago
5 0
The frequency will decrease because the waves are getting farther and farther apart and if they and as that happens with shorter and shorter so they decrease
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Explain how heat would change the density of a parcel of air
BartSMP [9]
<span>Heat would make the molecules move faster so they would spread out therefore making air less dense.
Less dense means less packed. Heat increase the kinetic energy</span>
6 0
4 years ago
Using the balanced equation for the next few questions: 4 Fe(s) + 30 (9) - 2Fe2O3(s)
stira [4]

Answer:

0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Fe: 4 moles
  • O₂: 3 moles
  • Fe₂O₃: 2 moles

You can apply the following rule of three: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, 0.15 moles of Fe produce how many moles of Fe₂O₃?

moles of Fe_{2} O_{3} =\frac{0.15 moles of Fe*2 moles of Fe_{2} O_{3}  }{4 moles of Fe}

moles of Fe₂O₃= 0.075

<u><em>0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.</em></u>

5 0
3 years ago
When a 3.80 g sample of C8H18(l) is burned in a bomb calorimeter, the temperature of the calorimeter rises by 27.3 oC. The heat
Fudgin [204]

<u>Answer:</u> The enthalpy of the reaction is -5112.5 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 6.18 kJ/°C

\Delta T = change in temperature = 27.3°C

Putting values in above equation, we get:

q=6.18kJ/^oC\times 27.3^oC=168.714kJ

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of octane = 3.80 g

Molar mass of octane = 114 g/mol

Putting values in above equation, we get:

\text{Moles of octane}=\frac{3.80g}{114g/mol}=0.033mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta E=\frac{q}{n}

where,

q = amount of heat released = -168.714 kJ

n = number of moles = 0.033 moles

\Delta E = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta E=\frac{-168.714kJ}{0.033mol}=-5112.5kJ/mol

Hence, the enthalpy of the reaction is -5112.5 kJ/mol

4 0
3 years ago
Looking at the picture showing water in 3 different states notice the Box above each pictures showing how the water particles ar
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To answer this question, I need to know what the picture looks like.
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3 years ago
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