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3 years ago

How many particles are present in a 56.9 mole sample of calcium hydroxide?

Chemistry

1 answer:

AleksAgata [21]3 years ago

5 0

Answer:

Particles? Calcium hydroxide does not exist as discrete molecules, but as a network solid. The only way you would have separate particles, is if the calcium hydroxide was dissolved in a boatload of water. Ca(OH)2 is not all that soluble in water. Nonetheless, assume a lot of water, enough to dissolve 56.9 moles.

Ca(OH)2 --> Ca2+ + 2OH-

56.9 moles Ca(OH)3 x (3 moles ions / 1 mol Ca(OH)2) = 170.7 mol ions

==================

Percent composition of CuNO3......molar mass = 125.5 g/mol

Cu.... 1 x 63.5 / 125.5 x 100 = 50.6% Cu

N ......1 x 14.0 / 125.5 x 100 = 11.2% N

O .....3 x 16.0 / 125.5 x 100 = 38.2% O

(hope this helps can i plz have brainlist :D hehe)

Explanation:

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AnnZ [28]

Answer:

I think its the first one. unless there is more to the question

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3 years ago

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Step2247 [10]

Answer:

See explanation

Explanation:

The equation of the reaction is;

C3H8 + 5O2 ----> 3CO2 + 4H2O

Number of moles of C3H8 = 132.33g/44g/mol = 3 moles

1 mole of C3H8 yields 3 moles of CO2

3 moles of C3H8 yields 3 × 3/1 = 9 moles of CO2

Number of moles of oxygen = 384.00 g/32 g/mol = 12 moles

5 moles of oxygen yields 3 moles of CO2

12 moles of oxygen yields 12 × 3/5 = 7.2 moles of CO2

Hence C3H8 is the limiting reactant.

Mass of CO2 produced = 9 moles of CO2 × 44 g/mol = 396 g of CO2

1 moles of C3H8 yields 4 moles of water

3 moles of C3H8 yields 3 × 4/1 = 12 moles of water

Mass of water = 12 moles of water × 18 g/mol = 216 g of water

b) Actual yield = 269.34 g

Theoretical yield = 396 g

% yield = actual yield/theoretical yield × 100/1

% yield = 269.34 g /396 g × 100

% yield = 68%

4 0

3 years ago

At lunch, the babysitter gives Tanya and Damien each a chocolate candy. Tanya puts her candy on her plate. Damien saves his cand

evablogger [386]

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3 years ago

Complete the following table. Tell if the molecule is polar or nonpolar, draw the Lewis dot structure for the molecule, tell wha

andrew11 [14]

The complete table is shown in figure

a) NH3 is polar as the bonds between N and H are polar. Due to asymmetry in the molecule the molecule is polar

The shape of molecule is trigonal pyramidal while its electronic geometry is tetrahedral.

b) CO2: it is a non polar molecule with polar bonds. The molecule becomes non polar as the dipole moment cancel each other. [Dipole moment is a vector quantity]

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3 years ago

Read 2 more answers

Find the number of moles of water that can be formed if you have 170 mol of hydrogen gas and 80 mol of oxygen gas. Express your

Sav [38]

<u>Answer:</u> The amount of water that can be formed is 160 moles

<u>Explanation:</u>

We are given:

Moles of hydrogen gas = 170 moles

Moles of oxygen gas = 80 moles

The chemical equation for the reaction of hydrogen gas and oxygen gas follows:

$2H_2+O_2\rightarrow 2H_2O$

By Stoichiometry of the reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas

So, 80 moles of oxygen gas will react with = $\frac{2}{1}\times 80=160mol$ of hydrogen gas

As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of oxygen gas produces 2 moles of water

So, 80 moles of oxygen gas will produce = $\frac{2}{1}\times 80=160moles$ of water

Hence, the amount of water that can be formed is 160 moles

3 0

3 years ago