Answer:
the angular velocity increase by a factor of 2
Explanation:
using the law of the conservation of the angular momentum
where is the inicial angular momentum and is the final angular momentum.
also, the angular momentum can be calculated by:
L = IW
where I is the inertia momentum and the W is the angular velocity.
so:
we know that then,
solving for :
Answer:
Tension upwards
Force downward
Explanation:
Since the weight of the strut is uniform therefore it can be considered as a uniformly distributed load of 400 over a mass-less beam.
According to the given conditions one end of the strut is attached to a hinge and the other is loaded with a sign of 200 N and supported by a cable in the middle of the span of strut as shown in the schematic.
<u>Now, for the equilibrium condition:</u>
Forces are balanced:
i.e.
.....................(1)
Moment about any point is balanced:
<u>Taking moment about the hinge point:</u>
upwards
Now put this value in eq. (1)
i.e. negative sign denotes opposite direction to the presumed one.
downward
Answer:
D. Newton's third law of motion
The final velocity of the red barge in the collision elastic is 0.311 m/s when it collides with blue barge pf mass 1000000 kg.
Final velocity(v3) of the red barge is calculated by following formula
m1×v1+ m2×v2= (m1+m2)v3
Substituting the value of m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/s
150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3
37500+ 320000= 1150000×v3
357500= 1150000×v3
v3= 0.311 m/s
<h3>What is elastic collision velocity? </h3>
- The velocity of the target particle after a head-on elastic impact in which the projectile is significantly more massive than the target will be roughly double that of the projectile, but the projectile velocity will remain virtually unaltered.
For more information on elastic collision velocity kindly visit to
brainly.com/question/29051562
#SPJ9