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lozanna [386]
3 years ago
7

Thermal equilibrium is reached when______________.

Physics
2 answers:
Luden [163]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

When there is no exchange of heat between two substances which are physically connected to each other then it is said that thermal equilibrium has reached.

Also at thermal equilibrium the temperature for two objects or substance becomes same.  

Thus, we can conclude that out of the given options thermal equilibrium is reached when two objects in contact with each other are the same temperature.

Art [367]3 years ago
4 0
<span>two objects in contact with each other are the same temperature</span>
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Define the law of universal gravitation in your own words.
Firdavs [7]
Newton's law of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers
7 0
3 years ago
A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is to have the actor fall on hi
tekilochka [14]

Answer:

The maximum mass that can fall on the mattress without exceeding the maximum compression distance is 16.6 kg

Explanation:

Hi there!

Due to conservation of energy, the potential energy (PE) of the mass at a height of 3.32 m will be transformed into elastic potential energy (EPE) when it falls on the mattress:

PE = EPE

m · g · h = 1/2 k · x²

Where:

m = mass.

g = acceleration due to gravity.

h = height.

k = spring constant.

x = compression distance

The maximum compression distance is 0.1289 m, then, the maximum elastic potential energy will be the following:

EPE =1/2 k · x²

EPE = 1/2 · 65144 N/m · (0.1289 m)² = 541.2 J

Then, using the equation of gravitational potential energy:

PE = m · g · h =  541.2 J

m =  541.2 J/ g · h

m = 541.2 kg · m²/s² / (9.8 m/s² · 3.32 m)

m = 16.6 kg

The maximum mass that can fall on the mattress without exceeding the maximum compression distance is 16.6 kg.

6 0
3 years ago
Who’s of the following is classified as a salt: ammonia or sodium chloride?
Temka [501]

Sodium Chloride could be classified as a salt.

8 0
3 years ago
Does gravity have an effect on the potential difference of a battery?
Sonja [21]

Answer: The correct answer is "No".

Explanation:

Gravity: It is the force which causes object to fall on the earth. It is the force which attracts bodies towards each other.

Potential difference: It is defined as the potential acting between the two points. The work done in moving the unit positive charge from one location to the another location.

The potential difference in battery is caused by the electrodes. There are two terminals in battery: Negative terminal which is at lower potential and Positive terminal which is at higher potential. It forces the electrons to flow in the circuit which constitutes the current.

The gravity and the potential difference have no relation between them.

Therefore, gravity have no effect on the potential difference of a battery.

5 0
3 years ago
Practice: The speed of sound at sea level is normally about 340 m/s. A car honks its horn as it drives toward an observer. The f
stepan [7]

Answer:

25.5 m/s

Explanation:

The Doppler effect occurs when there is relative motion between a source of a wave and an observer. In such situation, there is a shift in the apparent frequency of the wave perceived by the observer.

The formula that gives the apparent frequency perceived by the observer is:

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the real frequency of the wave

f' is the apparent frequency of the wave

v is the speed of the wave

v_s is the velocity of the source (negative if the source is moving towards the observer, positive otherwise)

v_o is the velocity of the observer (positive if the observer is moving towards the source, negative otherwise)

In this problem:

v = 340 m/s is the speed of sound

f = 800 Hz is the frequency of the horn

f' = 860 Hz is the apparent frequency

v_o=0 (the observer is at rest)

Re-arranging the equation for v_s, we can find the velocity of the horn and the driver:

f'=\frac{v}{v-v_s}f\\(v-v_s)f'=vf\\vf'-v_sf'=vf\\v_s=v\frac{f'-f}{f'}=(340)\frac{860-800}{860}=25.5 m/s

So, 25.5 m/s towards the observer.

3 0
3 years ago
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