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lozanna [386]
3 years ago
7

Thermal equilibrium is reached when______________.

Physics
2 answers:
Luden [163]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

When there is no exchange of heat between two substances which are physically connected to each other then it is said that thermal equilibrium has reached.

Also at thermal equilibrium the temperature for two objects or substance becomes same.  

Thus, we can conclude that out of the given options thermal equilibrium is reached when two objects in contact with each other are the same temperature.

Art [367]3 years ago
4 0
<span>two objects in contact with each other are the same temperature</span>
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Vector A has a magnitude of 16 m and makes an angle of 44° with the positive x axis. Vector B also has a magnitude of 13 m and i
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Answer with explanation:

The given vectors in are reduced to their componednt form as shown

For vector A it can be written as

\overrightarrow{v}_{a}=16cos(44^{o})\widehat{i}+16sin(44^{o})\widehat{j}

Similarly vector B can be written as

\overrightarrow{v}_{b}=-13\widehat{i}

Hence The sum and difference is calculated as

\overrightarrow{v}_{a}+\overrightarrow{v}_{b}=16cos(44^{o})\widehat{i}+16sin(44^{o})\widehat{j}+(-13\widehat{i})\\\\\overrightarrow{v}_{a}+\overrightarrow{v}_{b}=(16cos(44^{o})-13)\widehat{i}+16sin(44^{o})\widehat{j}\\\\\therefore \overrightarrow{v}_{a}+\overrightarrow{v}_{b}=-1.49\widehat{i}+11.11\widehat{j}\\\\\therefore |\overrightarrow{v}_{a}+\overrightarrow{v}_{b}|=\sqrt{(-1.49)^{2}+11.11^{2}}=11.21m

The direction is given by

\theta =tan^{-1}\frac{r_{y}}{r_{x}}\\\\\theta =tan^{-1}\frac{11.11}{-1.49}=97.64^{o}with positive x axis.

Similarly

\overrightarrow{v}_{a}-\overrightarrow{v}_{b}=16cos(44^{o})\widehat{i}+16sin(44^{o})\widehat{j}-(-13\widehat{i})\\\\\overrightarrow{v}_{a}-\overrightarrow{v}_{b}=(16cos(44^{o})+13)\widehat{i}+16sin(44^{o})\widehat{j}\\\\\therefore \overrightarrow{v}_{a}-\overrightarrow{v}_{b}=24.51\widehat{i}+11.11\widehat{j}\\\\\therefore |\overrightarrow{v}_{a}-\overrightarrow{v}_{b}|=\sqrt{(24.51)^{2}+11.11^{2}}=26.91m

The direction is given by

\theta =tan^{-1}\frac{r_{y}}{r_{x}}\\\\\theta =tan^{-1}\frac{11.11}{24.51}=24.38^{o}with positive x axis.

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Answer:

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Explanation:

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Answer:

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