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Anettt [7]
3 years ago
12

The amount of light that enters the pupil is controlled by the: retina. lens. inis.

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer: The amount of light that enters the pupil is controlled by the Iris

Explanation:

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The crystal in a digital watch oscillates at a rate of 215 Hz. If the maximum displacement of one crystal face (measured from on
Marizza181 [45]

The maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.

<h3>Maximum speed of the face</h3>

v = fλ

where;

  • f is frequency of the wave
  • λ is the wavelength

<h3>Angular speed of the wave</h3>

ω = 2πf

v(max) = ωA

v(max) = 2πfA

where;

  • A is amplitude of the wave

v(max)  = 2π(215)(50 x 10⁻⁹ m)

v(max) = 6.75 x 10⁻⁵ m/s

Thus, the maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.

Learn more about maximum speed here: brainly.com/question/4931057

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4 0
2 years ago
Water is poured into a bowl at a constant rate of 17.0 cm^3/s. The bowl has a circular cross section, but does not have a unifor
7nadin3 [17]

Answer:

10.29 cm/s

Explanation:

Discharge in to the bowl = 17.0 cm³/s

Diameter of the bowl, d₁ = 1.45 cm

Now,

Rate at which water level rise at its diameter = \frac{\textup{Discharge}}{\textup{Area of cross-section}}

also,

Area of cross-section = \frac{\pi}{\textup{4}}\times1.45^2

or

Area of cross-section = 1.651 cm²

Therefore,

Rate at which water level rise at its diameter = \frac{\textup{17}}{\textup{1.651}}

or

Rate at which water level rise at its diameter = 10.29 cm/s

8 0
4 years ago
When a hair dryer is being used, one of the energy transformations that takes place is
Maru [420]
Hello,

The answer is B) <span>electrical to mechanical.
</span><span>
When a hair dryer is being used, one of the energy transformations that takes place is </span>electrical to mechanical. Once you plug the hair dryer into the outlet, an electric current flows, starting the mechanical hair dryer.

Faith xoxo<span />
3 0
3 years ago
Read 2 more answers
Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d
alex41 [277]

Answer:

v=18.89\frac{m}{s}

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)

Solving N from (2) and replacing in (1):

N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}

Replacing and solving for v:

gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}

4 0
4 years ago
A speeding car is pulling away from a police car. The police car is moving at 30 m/s. The radar gun in the police car emits an e
Gekata [30.6K]

Answer:

65.625 m/s

Explanation:

F=20\times 10^9 Hz

\Delta F=F_r-F_t=4750 Hz

c = Speed of light = 3×10⁸ m/s

Relative speed

v=\frac{\Delta F}{2F}\times c\\\Rightarrow v=\frac{4750}{2\times 20\times 10^9}\times 3\times 10^8\\\Rightarrow v=35.625\ m/s

Relative speed = 35.625 m/s

Velocity of speeder = Velocity of police car + Relative speed

⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s

∴ Velocity of speeder is 65.625 m/s

6 0
4 years ago
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