Answer:
The major product formed is a benzyl allyl compound, namely 2-methylene propylbenzene
Explanation:
<u>Part 1.</u>
The product formed from this Wittig reaction with phosphonium ylide is a phenylallyl compound, 2-methylene propylbenzene. Structure and reaction synthesis is attached in file.
<u>Part 2</u>
The types of transformation involved are:
- alkylation (as there is a transfer of alkyl group)
- addition (reaction of ylide)
The answer is H—F. Fluorine is the most electronegative of the four halogens (and, in fact, of all the elements), so it does the best job of gathering the shared electrons to itself. Therefore, the bond with F is the most polar
Answer:
wavelength (λ) = 2.73 E-4 m
frecuency (f) = 1.10 E12 s-1
Explanation:
Stefan-Boltzmann law:
- intensity of the radiation for a black body (W) = σ.(T)∧4
∴ σ = 5.670 E-8 W/m²(K)∧4
∴ T = 298 K
⇒ W = (5.670 E-8 W/m²K∧4)×(298 K)∧4
⇒ W = 447.145 W/m² = 447.145 J/s.m²
assuming an area of 1 m²
⇒ W = 447.145 J/s
Rayleigh-Jeans's law:
∴ Black body radiation at a specific wavelength (Bλ(T)):
⇒ Bλ(T) = ( 2 c.k.T ) / (λ)∧4
∴ c = 3 E8 m/s.....velocity of speed
∴ k = 1.38065 E -23 J/K.........Boltzmann's constant
∴ Bλ(T) = 447.145 J/s.m²
⇒ (λ)∧4 = ((2)(3 E8 m/s)(1.38065 E-23 J/K)(298 K)) / (447.145 J/s)
⇒ λ = (5.521 E-15)∧(1/4)
⇒ λ = 2.73 E-4 m
⇒ f = (3 E8 m/s) / (2.73 E-4 m)
⇒ f = 1.10 E12 s-1
Answer:
Ammonium sulfate decomposes upon heating above 250 °C, first forming ammonium bisulfate. Heating at higher temperatures results in decomposition into ammonia, nitrogen, sulfur dioxide, and water. As a salt of a strong acid (H2SO4) and weak base (NH3), its solution is acidic; pH of 0.1 M solution is 5.5.
