Answer:
The original concentration of the acid was 0.605 M
Explanation:
Step 1: Data given
Volume of gas = 177.6 mL = 0.1176 L
Temperature = 25.8 °C = 298.95 K
Pressure = 799.7 torr = 799.7/ 760 = 1.0522368 atm
Volume of acid needed to react = 12.6 mL = 0.0126 L
Step 2: Calculate moles
p*V = n*R*T
n = (p*V)/(R*T)
⇒with n = the number of moles = TO BE DETERMINED
⇒with p = the pressure of the gas = 799.7 torr = 1.0522368 atm
⇒with V = the volume of the gas = 177.6 mL = 0.1776 L
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 25.8 °C = 298.95 K
n = 0.007618 moles
Step 3: Calculate original concentration
We need 0.007618 moles of acid to react with the same amount of moles gas
Concentration acid = moles / volume
Concentration acid = 0.007618 moles / 0.0126 L
Concentration acid = 0.605 M
The original concentration of the acid was 0.605 M
