Answer:
This type of meat is substance. If you were talking about meters then it would be a system of measurement.
Answer:
![r_{He}=169.7m/s](https://tex.z-dn.net/?f=r_%7BHe%7D%3D169.7m%2Fs)
Explanation:
Hello there!
In this case, since this problem can be understood via the Graham's law, which states that states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight, which can be extrapolated to the rate, we have:
![\frac{r_{O_2}}{r_{He}} =\sqrt{\frac{M_{He}}{M_{O_2}} }](https://tex.z-dn.net/?f=%5Cfrac%7Br_%7BO_2%7D%7D%7Br_%7BHe%7D%7D%20%3D%5Csqrt%7B%5Cfrac%7BM_%7BHe%7D%7D%7BM_%7BO_2%7D%7D%20%7D)
Thus, since the molar mass of helium is 4.0 g/mol and that of oxygen is 16.0 g/mol, we solve for the average velocity of helium as shown below:
![r_{He}=r_{O_2}\sqrt{\frac{M_{He}}{M_{O_2}} }\\\\r_{He}=480m/s\sqrt{\frac{4.0g/mol}{32.0g/mol} }\\\\r_{He}=169.7m/s](https://tex.z-dn.net/?f=r_%7BHe%7D%3Dr_%7BO_2%7D%5Csqrt%7B%5Cfrac%7BM_%7BHe%7D%7D%7BM_%7BO_2%7D%7D%20%7D%5C%5C%5C%5Cr_%7BHe%7D%3D480m%2Fs%5Csqrt%7B%5Cfrac%7B4.0g%2Fmol%7D%7B32.0g%2Fmol%7D%20%7D%5C%5C%5C%5Cr_%7BHe%7D%3D169.7m%2Fs)
Regards!
Answer: Because acetic acid in solution exists as a mixture of acetic acid & dissociated acetic acid (acetate)
Hope this helps!
Answer:
A. 21 J
Explanation:
Your temperature change is 10 degrees Celsius, or 10 Kelvin, it makes no difference either way.
Cp = 2.06 J/g•K
Multiply by the temperature change to just get J/g
2.06 J/g•K • 10 K = 20.6 J/g ≈ 21 J/g