Answer:
See the answer below
Explanation:
From the original equation in the image, the mole ratio of C:CO2:CO is 1:1:2. This means that for every 1 mole of C and CO2, 2 moles of CO would be produced.
Now, looking at the simulation below the equation of the reaction, 3 moles of C and 8 moles of CO2 were supplied as input. Applying this to the original equation of reaction, C seems to be a limiting reagent for the reaction because the ratio of C to CO2 should 1:1.
Hence, taking all the 3 moles of C available means that only 3 moles out of the available 8 for CO2 would be needed. 3 moles c and 3 moles CO2 means that 6 moles CO would be produced (remember that the ratio remains 1:1:3 for C, CO2, and CO). This means that 5 moles CO2 would be leftover.
<em>In other words, all the 3 moles C would be consumed, 3 out of 8 moles CO2 would be consumed, and 6 moles CO would be produced while 5 moles CO2 would be leftover. </em>
Answer:
<em>The correct option is a) Precipitate: silver sulfate
</em>
<em>
</em>
<em>Net Ionic: 2Ag+ + SO42 →Ag2SO4</em>
Explanation:
When sodium sulfate reacts with silver nitrate, the following reaction occurs:
2AgNO3 + Na2SO4 → Ag2SO4 + 2NaNO3
The NaNO3 is easily soluble in water. However, silver ions form an insoluble solid with SO4. The Ag+ in this compound will be a cation having a positive charge. The SO4- will be an anion having an negative charge.
The table with solubility rules show that the sulfates of Ag+, Ca+, Sr2+, Ba2+, Hg22+ and Pb2+ are insoluble.
mol CO₂ = 9.6
mol N₂ = 4.8
mol O₂ = 0.8
mol H₂O = 8
<h3>Further explanation</h3>
Reaction
4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O
mol CO₂
mol N₂
mol O₂
mol H₂O
A glucose molecule is completely broken down to carbon dioxide and water in glycolysis and the citric acid cycle, but together these two<span> processes yield only a few molecules of ATP.</span>
