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3 years ago

What should you do if the high power objective lens touches or breaks the cover slip?

Chemistry

1 answer:

saul85 [17]3 years ago

6 0

Tell your teacher. They'll know what to do and it's best to report it to them.

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A student will measure and record the growth of two flowering plants every day for 28 days. Plant A will be watered and fertiliz

mestny [16]

The conclusion that would support the students prediction is B) Plant "A" grows taller than Plant "B".
If the student thinks that adding fertilizer to the plant would help it grow then answer B) would make the most sence.

5 0

3 years ago

Read 2 more answers

What's the definition of soil composition ( 17 points ) !!! I NEED HELP NOW

Maru [420]

Soil composition refers to the nutrients and various other substances present in the soil. These are categorized into four basic categories: water, air, organic matter and minerals.

7 0

3 years ago

If a 95.27 mL sample of acetic acid (HC2H3O2) is titrated to the equivalence point with 79.06 mL of 0.113 M KOH, what is the pH

KATRIN_1 [288]

Answer:

8.73

Explanation:

The concentration of acetic acid can be determined as follows:

$M_1V_1 = M_2V_2\\(KOH) = (CH_3COOH)$

$M_{KOH}=0.113 M\\V_{KOH}=79.06 mL$

$V_{CH_3COOH}=95.27 \\\\M_{CH_3COOH)=?????$

$M_{CH3COOH} = \frac{M_{KOH}*V_{KOH}}{V_{CH_3COOH}}$

$M_{CH3COOH} = \frac{0.113*79.06}{95.27}$

$M_{CH3COOH} = 0.094 M$

Moles of $CH_3COOH$ = $95.27* 10^{-3}* 0.094$

=0.0090 moles

Moles of $KOH = 79.06*10^{-3}*0.113$

= 0.0090 moles

The equation for the reaction can be expressed as :

$CH_3COOH$ $+$ $KOH$ -----> $CH_3COO^{-}K^+$ $+$ $H_2O$

Concentration of $CH_3COO^{-$ ion = $\frac{0.0090}{Total volume (L)}$

= $\frac{0.0090}{(95.27+79.06)} *1000$

= 0.052 M

Hydrolysis of $CH_3COO^{-$ ion:

$CH_3COO^{-$ $+$ $H_2O$ -----> $CH_3COOH$ $+$ $OH^-$

$K = \frac{K_w}{K_a} = \frac{x*x}{0.052-x}$

⇒ $\frac{10^{-14}}{1.82*10^{-5}}= \frac{x*x}{0.052-x}$

= $0.5494*10^{-9}= \frac{x*x}{0.052-x}$

As K is so less, then x appears to be a very infinitesimal small number

0.052-x ≅ x

$0.5494*10^{-9}= \frac{x^2}{0.052}$

$x^2 = 0.5494*10^{-9}*0.052$

$x^2 = 0.286*10^{-10$

$x = \sqrt{0.286*10^{-10$

$x =0.535*10^{-5}M$

$[OH] = x =0.535*10^{-5}$

$pOH = -log[OH^-]$

$pOH = -log[0.535*10^{-5}]$

$pOH = 5.27$

pH = 14 - pOH

pH = 14 - 5.27

pH = 8.73

Hence, the pH of the titration mixture = 8.73

8 0

3 years ago

what is ( H+) and (OH-) in a healthy person's blood that has a PH of 7.50 assume that the temperature of the blood is 298 K.

AlekseyPX

pH = - log [H⁺]

pH = 7.5

$\tt [H^+]=10^{-7.5}=3.16\times 10^{-8}$

pH + pOH = 14

7.5 + pOH = 14

pOH = 6.5

$\tt [OH^-]=10^{-6.5}=3.16\times 10^{-7}$

5 0

2 years ago

Which statement best explains why sugar water can be easily separated?

VladimirAG [237]

Answer:

Sand has a strong non-polar covalent connection, that prevents water to break it down.

Explanation:

Sand being composed of quartz and small particulars of minerals can only be dissolved in hot acids, unlikd sugar which can easily be broken down by water, due to the large magnetic molecular propery of water and the ability to evolve sugar in an Intermolecular manner.

7 0

3 years ago