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MAXImum [283]
3 years ago
12

Flammabilty. Is a chemical property that tells whether a substance reacts in the presence of carbon dioxide try or false

Chemistry
2 answers:
Bogdan [553]3 years ago
8 0
False

Flammability occurs under extreme amounts of heat spark, and any other forms of ignition. A fire needs oxygen to spread not carbon dioxide.
beks73 [17]3 years ago
4 0

Answer:

False

Explanation:

Flammability is a chemical property that tells whether a substance reacts in the presence of extreme heat, spark, or another form of ignition.

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Need answer asap 4 both
marishachu [46]

The persistence of vision is regarded as an optical illusion but it is actually part of human physiology.

<h3>What is persistence of vision?</h3>

The term persistence of vision is the idea that an object is able to remain is sight for a long time even when the object has been removed. This is often used by performers to create a remarkable impression on the audience. The persistence of vision is regarded as an optical illusion but it is actually part of human physiology.

The way that a performance can be designed to make the audience to know that this is the most important scene is called follow through.

Learn more about optical illusion:brainly.com/question/28179807

#SPJ1

7 0
1 year ago
Which two of Earth's spheres interact when the rainfall in a region increases after a volcanic eruption?
Salsk061 [2.6K]

Answer:

Geosphere and Hydrosphere

Explanation:

Rain is water, and the volcanic eruption from the valcano is rock

8 0
2 years ago
A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i
Damm [24]

The correct answer is A 0.75 atm


4 0
3 years ago
Read 2 more answers
Are people made up of matter? Do they have mass?
GaryK [48]
Yes. Everything is made up of mass. If it takes up space, it has mass
3 0
3 years ago
he heat of fusion of tetrahydrofuran is . Calculate the change in entropy when of tetrahydrofuran melts at . Be sure your answer
lana [24]

Answer:

\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Explanation:

Hello.

In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

\Delta S=\frac{n*\Delta H}{T}

Whereas n accounts for the moles which are computed below:

n=5.9g*\frac{1mol}{72g} =0.082mol

Thus, the entropy turns out:

\Delta S=\frac{0.0819mol*8.5 kJ/mol}{(-108.5+273.15)K}\\\\\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Best regards.

3 0
3 years ago
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