All categories

3 years ago

What is the usual charge on an ion from group 7a

1 answer:

4 0

Group 7a would have an ion charge of -1 because it has 7 valence electrons and it wants to gain one more electron(which is negative) to have a full shell of 8

You might be interested in

What are the distinguishing features of each extraction process: pyrometallurgy, electrometallurgy, and hydrometallurgy? Explain

Tatiana [17]

<h3>1.Pyrometallurgy</h3>

This techniques involves the high temperature at which the Chemical reactions took place between the gases and solids.

Pyrometallurgy involves calcination, Roasting and smelting process.

<h3> 2.Electrometallurgy</h3>

This technique involves the metallurgy operations that took place in electrolytic cell.

Electro- winning and Electro-refining are some of the electrometallurgy process

<h3> 3. Hydrometallurgy</h3>

Reactions involves aqueous solutions to extract metal, use this technique.

Hydrometallurgy involves precipitation , distillation , adsorption and solid extraction operations.

Now,

Type of metallurgy are used in the production of Fe is Roasting and Smelting.

<h3>What is Roasting?</h3>

Ore is heated strongly with other substances, usually with Oxygen.
Process temperature is below the melting point.
Some of Impurities is removed as volatile substance.

In this reaction,

FeO changes to Fe₂O₃ to prevent the loss of iron during smelting.

4FeO +O₂→ Fe₂O₃.

Now,

<h3> What is Smelting?</h3>

The oxides of less electropositive metals like Pb, Zn, Fe, Sn, etc.
These are reduced by strongly heating with coal or coke.
Reduction of the oxide with Carbon at high temperature is known as Smelting.

Thus from the above conclusion we can say that , metallurgy are used in the production of Fe is Roasting and Smelting.

Learn more about Iron here: brainly.com/question/2535311

#SPJ4

7 0

2 years ago

What causes these H-bonds to form?

erik [133]

Answer: It is caused by the tendency of some atoms in molecules to attract electrons more than their accompanying atom.

4 0

3 years ago

Which shows the rational expression written using the least common denominator?

Alexandra [31]

Answer:

The first one.

$\frac{x + 1}{4x^{2} } and \frac{4(x + 1)}{4x^{2} }$

Explanation:

When comparing two fractions with variables like this, it's important to get to the same denominator in order to compare apples with apples and then be able to do not only comparisons but also perform additions/subtractions.

Question is which denominator to use and how to reach it.

In this case, the question and the answer choices do the work for you. The question asks which one is the LEAST common denominator, and the answers show denominators x² and 4x². The smallest of these is x², however, we can't simplify the first fraction to get to the x² denominator, so we'll go for the 4x².

So, the first fraction has already the correct denominator (4x²), we just have to transform the second one.

We multiply it by 1, expressed in a different way. Since we're multiplying by one, we're not affecting the value, just the way it looks.

Let's do it!, to get the denominator to go from x² to 4x², we need to multiply it by 4... so we'll multiply by 4/4 (which is 1, neutral for the multiplication).

$\frac{x + 1}{x^{2} } * \frac{4}{4} = \frac{4(x + 1)}{4x^{2} }$

And now you have both fractions on the same denominator, without having changed their value, just their looks

6 0

3 years ago

Solid sulfur dioxide, SO₂(s)

natali 33 [55]

A - Sulfur dioxide is an ion because it contains 2 or more elements, and it is a solid

4 0

3 years ago

2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?

Sophie [7]

<h3>Answer:</h3>

$\displaystyle 0.5 \ mol \ CO_2$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Moles
Compounds

<u>Stoichiometry</u>

Using Dimensional Analysis
Analyzing Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

[DA] Set up: $\displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.5 \ mol \ CO_2$

7 0

2 years ago