Answer:
The probability density (ψ2)
Explanation:
Indicates the probability of finding the electron in a certain region of space when it is squared ψ2.
This means that define2 defines the distribution of electronic density around the nucleus in three-dimensional space; a high density represents a high probability of locating the electron and vice versa.
The atomic orbital, can be considered as the electron wave function of an atom.
APPLICATIONS:
1.- Specify the possible energy states that the electron of the hydrogen atom can occupy and identify the corresponding wave functions medio, by means of a set of quantum numbers, with which an understandable model of the hydrogen atom can be constructed.
2.- It does not work for atoms that have more than one electron, but the problem is solved using approximation methods for polyelectronic atoms.
5/8=0.625 4/5=.8
5/8 because 5/8=0.625 and because its 2x you multiply 0.625 by 2=1.25 then you do 1.25+5=6.25 4/5=.8 6.25 times .8=5 5-4=1
X=5/8 or 0.625
Answer: B
Explanation:
A is evaporation. B is condensation. C is precipitation.
Answer:
(a) O = Valance Electrons (6), Inner electrons (8)
(b) Sn = Valance Electrons (2), Inner electrons (36)
(c) Ca = Valance Electrons (2), Inner electrons (20)
(d) Fe = Valance Electrons (2), Inner electrons (26)
(e) Se = Valance Electrons (6), Inner electrons (34)
