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Ksenya-84 [330]
4 years ago
13

A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume

is 6 L, and the final pressure is 8atm, what was the initial temperature of the argon? Please give answer WITHOUT the unit of KELVIN and round to the tenth position (two places to the right of the decimal). Example: 25.14 not 25.4K
Chemistry
1 answer:
Nitella [24]4 years ago
3 0
According to this formula:
(PiVi)/Ti = (PfVf)/Tf
when : Pi = intial pressure  /  Vi = intial volume  / Ti = intial temperture
   and:  pf = final pressure /  Vf = final volume  /  Tf = final temperture

Convert T from C° to Kelvin :
Tf = 30 + 273 = 303 K
by substitution in the previous formula :
(2 x 5 ) / Ti = (8 x 6) / 303
Ti = (303 x 10 ) / 48 = 63.125 K
Ti = 63.125 - 273 = - 209.88 C°


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Which of the following is a correct formula unit? PbCl AlP Li3Al ClO
zavuch27 [327]

Answer:  AIP  

There are two types of substances mixture and pure substance. Mixture has NO chemical formula and a pure substance has a chemical formula. There are two types of pure substances, elements (mono atomic and molecular) and compounds ( covalent and ionic).  

Ionic compounds do not exist in independent molecular form. They form three dimensional crystal lattice, in which each ion is surrounded by oppositely charged ion.  so the ratio of ion is called the formula unit  


3 0
4 years ago
Read 2 more answers
If there are 3.10 moles of O, how many moles of each of the compounds are present?
Burka [1]

Explanation:

The question pretty  much requires us to find the amount of moles of each compounds based on the number of moles of O given.

H2SO4

1 mol of H2SO4 contains 4 mol of O

x mol of H2SO4 would contain 3.10 mol of O

x = 3.10 * 1 / 4 = 0.775 mol of H2SO4

C2H4O2

1 mol of C2H4O2 contains 2 mol of O

x mol of C2H4O2 would contain 3.10 mol of O

x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2

NaOH

1 mol of NaOH contains 1 mol of O

x mol of NaOH would contain 3.10 mol of O

x = 3.10 * 1 / 1 = 3.10 mol of NaOH

3 0
3 years ago
Describe a method to calculate the average atomic mass of the sample in the previous question using only the atomic masses of li
alexira [117]

Answer:

Explanation:

To calculate their average atomic masses which is otherwise known as the relative atomic mass, we simply multiply the given abundances of the atoms and the given atomic masses.

The abundace is the proportion or percentage or fraction by which each of the isotopes of an element occurs in nature.

This can be expressed below:

        RAM = Σmₙαₙ

where mₙ is the mass of isotope n

           αₙ is the abundance of isotope n

for this problem:

RAM of Li = m₆α₆ + m₇α₇

       m₆ is mass of isotope Li-6

        α₆ is the abundance of isotope Li-6

       m₇ is mass of isotope Li-7

        α₇ is the abundance of isotope Li-7

3 0
3 years ago
Can someone explain to me step by step with the equation on how to do it thx
Tasya [4]

Answer:

h=1

c=12

there 8 h

then there are 5 c

Explanation:

6 0
3 years ago
Find the number of grams <br><br>4.00 moles of CU(CN)2 ​
USPshnik [31]

Answer:

462g

Explanation:

First, let us calculate the molar mass of Cu(CN)2. This is illustrated below:

Molar Mass of Cu(CN)2 = 63.5 + 2(12+14) = 63.5 + 2(26) = 63.5 + 52 = 115.5g/mol

Number of mole of Cu(CN)2 given from the question = 4moles

Mass = number of mole x molar Mass

Mass of Cu(CN)2 = 4 x 115.5

Mass of Cu(CN)2 = 462g

4 0
3 years ago
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