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Ksenya-84 [330]
3 years ago
13

A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume

is 6 L, and the final pressure is 8atm, what was the initial temperature of the argon? Please give answer WITHOUT the unit of KELVIN and round to the tenth position (two places to the right of the decimal). Example: 25.14 not 25.4K
Chemistry
1 answer:
Nitella [24]3 years ago
3 0
According to this formula:
(PiVi)/Ti = (PfVf)/Tf
when : Pi = intial pressure  /  Vi = intial volume  / Ti = intial temperture
   and:  pf = final pressure /  Vf = final volume  /  Tf = final temperture

Convert T from C° to Kelvin :
Tf = 30 + 273 = 303 K
by substitution in the previous formula :
(2 x 5 ) / Ti = (8 x 6) / 303
Ti = (303 x 10 ) / 48 = 63.125 K
Ti = 63.125 - 273 = - 209.88 C°


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30PTS EASY QUESTION
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Calculate the energy required to heat 322.0g of ethanol from −2.2°C to 19.6°C . Assume the specific heat capacity of ethanol und
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Answer:

There is 17.1 kJ energy required

Explanation:

Step 1: Data given

Mass of ethanol = 322.0 grams

Initial temperature = -2.2 °C = 273.15 -2.2 = 270.95K

Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K

Specific heat capacity = 2.44 J/g*K

Step 2: Calculate energy

Q = m*c*ΔT

⇒ m = the mass of ethanol= 322 grams

⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K

⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K

Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ

There is 17.1 kJ energy required

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