For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen,
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The allowable combination for the atomic orbital is n=3, l=1, =-1.
Three quantum numbers specify an atomic orbital:
- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.
- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),
- is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus;
values are integers from -l to =l(l limits ml)
For n = 3, l can have three values: 0, 1, and 2. Since values are integers from -l to 0 to +l, for l = 0 the value of
cannot be -1 (l = 0 has
= 0).
There are two l values that are consistent with n and values:
l=1 or 2
Therefore, the allowable condition is n=3, l=1, =-1.
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