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Sliva [168]
3 years ago
7

What is the standard deviation of the following data set:

Engineering
1 answer:
EastWind [94]3 years ago
3 0

Answer:

See Explanation

Explanation:

The question is incomplete as the data set are missing. However, I'll use the following data to answer your question:

<em>5,12,3,18,6,8,2,10 </em>

Start by calculating the mean:

Mean = \frac{\sum x}{n}

Mean= \frac{5+12+3+18+6+8+2+10}{8}

Mean= \frac{64}{8}

Mean = 8

Standard deviation is calculated using:

SD = \sqrt{\frac{(x_i - Mean)^2}{n}}

This gives:

SD = \sqrt{\frac{(5 - 8)^2+(12 - 8)^2+(3 - 8)^2+(18 - 8)^2+(6 - 8)^2+(8 - 8)^2+(2 - 8)^2+(10 - 8)^2}{8}}

SD = \sqrt{\frac{(-3)^2+(4)^2+(- 5)^2+(10)^2+(-2)^2+(0)^2+( - 6)^2+(2)^2}{8}}

SD = \sqrt{\frac{9+16+25+100+4+0+36+4}{8}}

SD = \sqrt{\frac{194}{8}}

SD = \sqrt{24.25}

SD = 4.92

<em>Apply the above steps in the original question, then you will get your correct answer.</em>

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Give five general principles involved in the process of sewage filtration?​
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Answer:

Some general principles are given below in the explanation segment.

Explanation:

Sewage treatment seems to be a method to extract pollutants from untreated sewage, consisting primarily of domestic sewage including some solid wastes.

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Which sentence is correct about the exergy of an empty (pressure around zero Pascal) tank with a volume of V, located in an envi
sineoko [7]

Answer:

The correct option is;

c.  the exergy of the tank can be anything between zero to P₀·V

Explanation:

The given parameters are;

The volume of the tank = V

The pressure in the tank = 0 Pascal

The pressure of the surrounding = P₀

The temperature of the surrounding = T₀

Exergy is a measure of the amount of a given energy which a system posses that is extractable to provide useful work. It is possible work that brings about equilibrium. It is the potential the system has to bring about change

The exergy balance equation  is given as follows;

X_2 - X_1 = \int\limits^2_1 {} \, \delta Q \left (1 - \dfrac{T_0}{T} \right ) - [W - P_0 \cdot (V_2 - V_1)]- X_{destroyed}

Where;

X₂ - X₁ is the difference between the two exergies

Therefore, the exergy of the system with regards to the environment is the work received from the environment which at is equal to done on the system by the surrounding which by equilibrium for an empty tank with 0 pressure is equal to the product of the pressure of the surrounding and the volume of the empty tank or P₀ × V less the work, exergy destroyed, while taking into consideration the change in heat of the system

Therefore, the exergy of the tank can be anything between zero to P₀·V.

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A hydraulic jump is induced in an 80 ft wide channel.The water depths on either side of the jump are 1 ft and 10 ft.Please calcu
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Answer:

a) 42.08 ft/sec

b) 3366.33 ft³/sec

c) 0.235

d) 18.225 ft

e) 3.80 ft

Explanation:

Given:

b = 80ft

y1 = 1 ft

y2 = 10ft

a) Let's take the formula:

\frac{y2}{y1} = \frac{1}{5} * \sqrt{1 + 8f^2 - 1}

10*2 = \sqrt{1 + 8f^2 - 1

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For velocity of the faster moving flow, we have :

\frac{V_1}{\sqrt{g*y_1}} = 7.416

V_1 = 7.416 *\sqrt{32.2*1}

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b) the flow rate will be calculated as

Q = VA

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c) The Froude number of the sub-critical flow.

V2.A2 = 3366.66

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Solving for V2, we have:

V_2 = \frac{3666.66}{80*10}

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\frac{V_2}{g*y_2} = \frac{4.208}{32.2*10}

F2 = 0.235

d) El = \frac{(y_2 - y_1)^3}{4*y_1*y_2}

El = \frac{(10-1)^3}{4*1*10}

= \frac{9^3}{40}

= 18.225ft

e) for critical depth, we use :

y_c = [\frac{(\frac{3366.66}{80})^2}{32.2}]^1^/^3

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