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Sliva [168]
2 years ago
7

What is the standard deviation of the following data set:

Engineering
1 answer:
EastWind [94]2 years ago
3 0

Answer:

See Explanation

Explanation:

The question is incomplete as the data set are missing. However, I'll use the following data to answer your question:

<em>5,12,3,18,6,8,2,10 </em>

Start by calculating the mean:

Mean = \frac{\sum x}{n}

Mean= \frac{5+12+3+18+6+8+2+10}{8}

Mean= \frac{64}{8}

Mean = 8

Standard deviation is calculated using:

SD = \sqrt{\frac{(x_i - Mean)^2}{n}}

This gives:

SD = \sqrt{\frac{(5 - 8)^2+(12 - 8)^2+(3 - 8)^2+(18 - 8)^2+(6 - 8)^2+(8 - 8)^2+(2 - 8)^2+(10 - 8)^2}{8}}

SD = \sqrt{\frac{(-3)^2+(4)^2+(- 5)^2+(10)^2+(-2)^2+(0)^2+( - 6)^2+(2)^2}{8}}

SD = \sqrt{\frac{9+16+25+100+4+0+36+4}{8}}

SD = \sqrt{\frac{194}{8}}

SD = \sqrt{24.25}

SD = 4.92

<em>Apply the above steps in the original question, then you will get your correct answer.</em>

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Answer:

import pandas pd

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price_dict = {}

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3 years ago
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Answer:

True

Explanation:

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It has a piece of 1045 steel with the following dimensions, length of 80 cm, width of 30 cm, and a height of 15 cm. In this piec
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Answer:

material remove in 3 min is 16790.4 mm³/s

Explanation:

given data

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width W = 30 cm

height H = 15 cm

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depth = 10 cm

mill toll diameter = 4 mm

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solution

first we find time taken for length of advance that is

time = \frac{length}{advance}

here advance is given as 0.001166 mts / sec

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7 0
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Who was part of dempwolf his firm when he first started
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Dempwolf created by John Augustus, Among the most prominent innovative solutions in Southern California Pennsylvania was established by Dempwolf with  brother Reinhardt or uncle's son Frederick entered the company of J.A. Dozens of structures in 10 states were engineered by Dempwolf.

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