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3 years ago

What is the basic formula for actual mechanical advantage?

Engineering

1 answer:

slavikrds [6]3 years ago

3 0

Answer:

Mechanical Advantage Formula

The efficiency of a machine is equal to the ratio of its output to its input. It is also equal to the ratio of the actual and theoretical MAs. But, it does not mean that low-efficiency machines are of limited use. An automobile jack, for example, have to overcome a great deal of friction and therefore it has low efficiency. But still, it is extremely valuable because small effort can be applied to lift a great weight.

Also, in another way the mechanical advantage is the force generated by a machine to the force applied to it which is applied in assessing the performance of the machine.

The mechanical advantage formula is:

MA = FBFA

Explanation:

MAmechanical advantageFBthe force of the object

FAthe effort to overcome the force

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A 50kg block of nickel at 90°C is dropped into an insulated tank that contains 0.5 m3 of liquid water at 25°C. Determine the fol

Valentin [98]

Answer:

a).Control volume

b). $C_{nickel}$ = 502.416 J/kg-K

c). $C_{water}$ = 4.187 kJ/kg-K

d). $T_{2}$ = 87.91°C

Explanation:

a). It is a control volume system because mass is varying in the system.

b). Specific heat of nickel is $C_{nickel}$ = 502.416 J/kg-K

c). Specific heat of water is $C_{water}$ = 4.187 kJ/kg-K

d).We know that

net energy transfer = change in internal energy

$m_{nickel}\times c_{nickel}(T_{2}-T_{nickel})=m_{water}\times c_{water}(T_{2}-T_{water})$

$m_{nickel}\times c_{nickel}(T_{2}-T_{nickel})=(volume_{water}\times density_{water})\times c_{water}(T_{2}-T_{water})$

$50\times 502.416\times (T_{2}-90)=(0.5\times 1000)\times 4.187\times (T_{2}-25)$

$25120.8\times (T_{2}-90)=2093.5\times (T_{2}-25)$

$T_{2}$ = 87.91°C

6 0

3 years ago

Read 2 more answers

Please help me with this question

kap26 [50]

Answer:

The current through each lamp is 0.273 Amperes

Power dissipated in each lamp is 0.082W

Explanation:

Battery v = 1.5 V

Each lamp has resistance, r = 1.1 Ohms

The 5 lamps in series will therefore have total resistance, R = 5 * 1.1 = 5.5 Ohms

The current through each lamp, I = v/R = 1.5 / 5.5 = 0.273 Amperes

Power dissipated in each lamp = I² * r = 0.273² * 1.1 = 0.082W

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3 years ago

A company, studying the relation between job satisfaction and length of service of employees, classified employees into three le

Wewaii [24]

Answer:

Below see details

Explanation:

A) It is attached. Please see the picture

B) First to calculate the overall mean,

μ=65∗25/75+80∗25/75+95∗25/75

μ=65∗25/75+80∗25/75+95∗25/75 = 80

Next to calculate E(MSTR) = σ2+(1/r−1) ∑ni(μi−μ)^2 = 5634

And E(MSE) = σ^2= 9

C) Yes, it is substantially large than E(MSE) in this case.

D) If we sampled 25 employees from each group, we are likely to get a F statistics to indicate differences of job satisfactions among three types of length of service of employees.