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denpristay [2]
3 years ago
8

A car traveled at a constant velocity of 70 mph from noon to 2:00 pm. At 3:00 pm the velocity of the car was 80 mph; and finally

at 4:30 pm the velocity of the car was 40 mph. Calculate the acceleration of the car between 3:00 and 4:30 pm. A) -40 mi hr2 B)-26.67 mi hr2 C)26.67 mi hr2 D) 40 mi hr2
Physics
1 answer:
enot [183]3 years ago
3 0
Acceleration is the result when the difference in final and initial speed is divided by time. From the given, the acceleration from 3:00 to 4:30 pm is calculated through the steps below,
                             acceleration = (40mph - 80 mph) / 1.5 h
                                                     -26.67 mi/h²
Thus, the answer is letter B. 
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Answer:

d) v1 = v2 = v3

Explanation:

This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.

At the original point we have, for the three balls:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

At the final point we have, for the three balls:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

Since we have E_i=E_f, and E_i is the same for all balls, then E_f is the same for all balls, which means that v_f, the final velocity, is the same for all balls.

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Answer: 909 m/s

Explanation:

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Mass of the bullet, m1 = 0.05 kg

Mass of the wooden block, m2 = 5 kg

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From the question, we would notice that there is just an object (i.e the bullet) moving before the collision. Also, even after the collision between the bullet and wood, the bullet and the wood would move as one object. Thus, we would use the conservation of momentum to solve

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0.05 * v1 = (0.05 + 5) * 9

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Thus, the original velocity of the bullet was 909 m/s

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