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3 years ago

Order from greatest to least 1.62 16.2% 15/20

Mathematics

2 answers:

Reika [66]3 years ago

5 0

Answer:

The order of the number from greatest to least is 1.62, 15/20, 16.2%

Step-by-step explanation:

Given: 1.62 16.2% 15/20

To order these data in descending order (i.e. from highest to least), follow the steps below

1. Convert all numbers to decimals

1.62

16.2% = 16.2/100

16.2% = 0.162

15/20 = 0.75

So, the number are 1.62, 0.162, 0.75

2. Compare the three decimals and arrange in descending order

1.62 > 0.75 > 0.162

This means that 1.62 is greater than 0.75 and 0.75 is greater than 0.162

By substituting 16.2% for 0.162 and 15/20 for 0.75, the order of the number from greatest to least is

1.62, 15/20, 16.2%

Pie3 years ago

3 0

Answer:

1.62,15/20,16.2%

Step-by-step explanation:

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option C. $-\frac{5}{13}$

Step-by-step explanation:

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3 years ago

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

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Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for h:

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for h.

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Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

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3 years ago

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3 years ago

Order from greatest to least 1.62 16.2% 15/20​

Order from greatest to least 1.62 16.2% 15/20