Answer:
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<em>sol</em><em>ution</em><em>,</em>
<em>Force=</em><em>4</em><em> </em><em>N</em>
<em>Distance</em><em>=</em><em>0</em><em>.</em><em>3</em><em> </em><em>m</em>
<em>Now</em><em>,</em>
<em>
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<em>hope</em><em> </em><em>this </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
A positively charged nucleus with two protons and two neutrons hope this helps :)
Answer:
1.71atm
Explanation:
The following were obtained from the question:
V1 (initial volume) = 6L
P1 (initial pressure) = 1atm
V2 (final volume) = 3.5L
P2 (final pressure) =?
Using the Boyle's law equation:
P1V1 = P2V2, the final pressure can be obtained as follow:
P1V1 = P2V2
1 x 6 = P2 x 3.5
Divide both side by 3.5
P2 = 6/3.5
P2 = 1.71atm
The final i.e the new pressure inside the piston is 1.71atm
Answer:
8.912x10^-18
Explanation:
-dn/dt = pANa/2piMRT
100 g = initial copper
Number of moles = 100/63.546
= 1.5736
Mass of copper left = 100-10.0168
= 89.9832
Moles = 89.9832/63.546
= 1.4160
dn = 1.4160-1.5736
= -0.1576
dt = 2 hrs
A = 3.23mm² = 3.23x10^-6
M = 63.546
T = 0.0821
T = 1508k
Na = 6.023x10²³
When we insert all these into the formula above
We get
P = 8.912x10^-18atm
