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likoan [24]
3 years ago
5

Pasteur's study of fermentation was critical to the development of microbiology because A. fermentation chemistry occurs in the

living body. B. it showed that microorganisms bring about chemical changes. C. it demonstrated that yeasts are involved in disease. D. the body undergoes rapid fermentation after death.
Chemistry
1 answer:
earnstyle [38]3 years ago
7 0

Answer:

B. It showed that microorganisms bring about chemical changes

Explanation:

In 1857 Pasteur was working to solve a problem with the distillers of Lille in wich in their barrels the alcoholic fermentation become in a  lactic fermentation, and of course, that was something that they didn't want. Throughout diferents studyes Pasteur discover that different microorganism where involved directly (where responsible) in different types of fermentation. That was the key to start the microbiology studies worldwide.

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Which of the following pairs contains a conjugate acid-base pair?
zzz [600]
Remember that a conjugate acid-base pair will differ only by one proton. 
None of the options you listed are conjugate acid-base pairs as none of them differ only by one proton (or H⁺)
An example of a conjugate acid-base pair would be NH₃ and NH₄⁺NH₃ + H₂O --> NH₄⁺ + OH⁻NH3 is the base, and NH₄⁺ is the conjugate acid
5 0
4 years ago
Suppose that you use a pair of chopsticks and apply a force of 1 N over a distance of 0.01 m. How much work do you do? If the ou
Leto [7]

Explanation:

Work done = force * perpendicular distance

= 1 * 0.01 = 0.01 joules

7 0
3 years ago
1. A solution is made by mixing 50mL of 2.0M K2HPO4 and 25mL of 2.0M KH2PO4. The solution is diluted to a final volume of 200mL.
Kazeer [188]

Answer:

The pH of the final solution is 7.15

Explanation:

50 mL of 2.0 M of K_2HPO_4 and 25 mL of 2.0 M of KH_2PO_4 were mixed to make a solution

Final volume of the solution after dilution = 200 mL

Final concentration of K_2HPO_4, [K_2HPO_4] = \frac{50 mL\times 2 M}{200 mL} = 0.5 M

Final concentration ofKH_2PO_4, [KH_2PO_4] = \frac{25 mL\times 2 M}{200 mL} = 0.25 M

We use Hasselbach- Henderson equation:

pH = pK_a+ log \frac{[salt]}{[acid]}pka of KH_2PO_4 = 6.85

Substituting the values:

pH = 6.85+ log \frac{0.5}{0.25}pH = 6.85+ log 2pH = 6.85+ 0.3 = 7.15

Therfore,  the pH of the final solution is 7.15

5 0
3 years ago
Ne, c4h10, is a component of natural gas that is used as fuel for cigarette lighters. the balanced equation of the complete comb
Simora [160]
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4 0
3 years ago
When a drawing of a circle made in the center of a piece of paper with a black marker gets wet, the marker bleeds, and as the wa
Ahat [919]

Answer:

Chromatography

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8 0
3 years ago
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