All categories

3 years ago

A calorie is another term for carbohydrate.TF

1 answer:

8 0

This is false. A carbohydrate is a carbon-based molecule that can be utilized by living organisms in order to produce energy. A calorie is a unit of energy often used to measure the amount of energy within food. Another example of energy unit is the Joule, more commonly used within physics.

You might be interested in

If a word ends with the suffix -logy, it pertains to the

spayn [35]

It means “the study of.” Think of it:
Those are subjects you study. It makes more sense than the other choices.

6 0

3 years ago

Read 2 more answers

Using the following reaction (depicted using molecular models), large quantities of ammonia are burned in the presence of a plat

Mila [183]

Answer:

17.65 grams of O2 are needed for a complete reaction.

Explanation:

You know the reaction:

4 NH₃ + 5 O₂ --------> 4 NO + 6 H₂O

First you must know the mass that reacts by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). For that you must first know the reacting mass of each compound. You know the values of the atomic mass of each element that form the compounds:

N: 14 g/mol
H: 1 g/mol
O: 16 g/mol

So, the molar mass of the compounds in the reaction is:

NH₃: 14 g/mol + 3*1 g/mol= 17 g/mol
O₂: 2*16 g/mol= 32 g/mol
NO: 14 g/mol + 16 g/mol= 30 g/mol
H₂O: 2*1 g/mol + 16 g/mol= 18 g/mol

By stoichiometry, they react and occur in moles:

NH₃: 4 moles
O₂: 5 moles
NO: 4 moles
H₂O: 6 moles

Then in mass, by stoichiomatry they react and occur:

NH₃: 4 moles*17 g/mol= 68 g
O₂: 5 moles*32 g/mol= 160 g
NO: 4 moles*30 g/mol= 120 g
H₂O: 6 moles*18 g/mol= 108 g

Now to calculate the necessary mass of O₂ for a complete reaction, the rule of three is applied as follows: if by stoichiometry 68 g of NH₃ react with 160 g of O₂, 7.5 g of NH₃ with how many grams of O₂ will it react?

$mass of O_{2} =\frac{7.5 g of NH_{3} * 160 g of O_{2} }{68 g of NH_{3} }$

mass of O₂≅17.65 g

17.65 grams of O2 are needed for a complete reaction.

3 0

3 years ago

In the balanced equation , CS2 + 3O2 = CO2 + 2SO2 , how many mol of O2 would react with 34.5 mol of CO2?

Arada [10]

Given:

Moles of CS2 (it cannot be CO2 as mentioned in the question, since O2 reacts with CS2 and not CO2) = 34.5 mol

To determine:

Moles of O2 undergoing the reaction

Explanation:

The reaction is-

CS2 + 3O2 → CO2 + 2SO2

Based on the stoichiometry: 3 moles of O2 reacts with 1 mole of CS2

therefore the moles of O2 that would combine with 34.5 moles of CS2 are

= 3 moles O2 * 34.5 moles CS2/1 mole CS2 = 103.5 moles

Ans: Around 104 moles of O2 would react with 34.5 moles of CS2

8 0

3 years ago

Read 2 more answers

Which element is used in light bulbs as a filament

mojhsa [17]

The element that is used in light bulbs as a filament is tungsten - this is almost always the case in halogen and incandescent bulbs. Tungsten is chosen for this purpose because of the fact it can withstand temperatures of up to 4,500 degrees, as well as being incredibly flexible.

8 0

3 years ago

Temperature, density, and pressure ______________ (increases, decreases) as depth ____________ (increases, decreases).

Alisiya [41]

Answer:

increase/increase

Explanation:

4 0

3 years ago

Read 2 more answers