Question

Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h7sh

Answer 1

Answer:

0.264 g of $CO_2$ can be formed from 288 mg of $O_2$

Explanation:

The balanced chemical equation is

$2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O$

The conversions are  

Mass in mg $O_2$ is converted to mass in g $O_2$  

Mass in g $O_2$ is converted to moles $O_2$ by dividing with molar mass  

Moles $O_2$ is converted to moles $CO_2$  by using the mole ratio of $O_2:CO_2$ is 9 : 6

Moles $CO_2$  is converted to mass $CO_2$ by multiplying with molar mass $CO_2$

mass in mg $O_2$  > mass in g $O_2$ >moles $O_2$ > moles $CO_2$ > mass $CO_2$

$288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}$

=0.264g (Answer)