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2 years ago

Name the salt produced if sodium carbonate reacts with dilute nitric acid ? Write the equation.

Chemistry

1 answer:

Angelina_Jolie [31]2 years ago

5 0

Answer:

2HNO3 +Na2CO3 → CO2 + H2O + 2NaNO3

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The best way seperate salt fron wateris with the use of

ExtremeBDS [4]

You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid. So, I would say maybe oil.

6 0

2 years ago

hich of the following statements is not true for an exothermic reaction? Question 2 options: The products have a higher heat con

yKpoI14uk [10]

Answer:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An endothermic process absorbs heat and cools the surroundings.

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3 years ago

Help me with this question so I can move on from it.

fomenos

Just look it up on google kodvjkngkrefsnjkvjfrnefsjkj

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3 years ago

Element A has a half-life of 10 days. A scientist measures out 200 g of this substance. After 30 days has passed, the scientist

myrzilka [38]

N=N₀*2^(-t/T)

N₀=200 g
T=10 d
t=30 d

N=200*2^(-30/10)=25 g

25 g will remain

4 0

3 years ago

Read 2 more answers

What is the mass of 1.58 moles of CH4

HACTEHA [7]

<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})$
Multiply/Divide: $\displaystyle 25.359 \ g \ CH_4$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0

3 years ago