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2 years ago

Write a polynomial function of least degree with integral coefficient that has the given zeros. -2, 2, 4, and 6

1 answer:

Natasha2012 [34]2 years ago

4 0

The polynomial function of the least degree with integral coefficient that has the given zeros is y = (x+2)(x-2)(x-4)(x-6). I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications about the said problem.

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PLEASE HELP 40 POINTS & BRAINLIEST!

Setler79 [48]

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3 years ago

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Shade the grid to represent the ratio 9/25. Then find a percent equivalent to the given ratio.

anzhelika [568]

Answers and workings in the attachment below.

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3 years ago

Can somebody help me please

Mrac [35]

Answer:
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2 years ago

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2 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$

Thus the solution is found

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2 years ago