All categories

3 years ago

Explain what it means to view a moving object from a frame of reference

1 answer:

5 0

When you look at an object in motion, the frame of reference is different depending on where you are when looking at this object.

For example, if you are in a train you can say that from your frame of reference the ground outside is moving compared to you and you are not moving or the train is not moving. From someone on the outside of the train, they can say that the train is moving compared to the ground and they are not moving.

Another example could be if you are driving in a car. You can say that the road is moving backwards compared to you and you are stationary. Someone standing on the sidewalk can say you are moving compared to the ground. You can also say that you are not moving since you are stationary in the car.

You might be interested in

A hunter is aiming horizontally at a monkey who is sitting in a tree. The monkey is so terrified when it sees the gun that it fa

Dvinal [7]

Answer:a) The bullet will miss the monkey because the monkey falls down while the bullet speeds straight forward.

Explanation: The bullet keeps as it aim( the monkey) unless it is redirected by an external force that could redirect it. Hence, the bullet speeds straight forward.

3 0

3 years ago

A laser beam of wavelength 600 nm is incident on two slits that are separated by 0.02 mm. What is the separation between adjacen

Liula [17]

Answer:

option D

Explanation:

given,

wavelength = 600 nm

width of separation = 0.02 mm

L = 5 m

for mth order maxima

$d \times \dfrac{y_m}{L}=m\lambda$

for (m+1)th order maxima

$d \times \dfrac{y_{m+1}}{L}=(m+1)\lambda$

now,

$y_m=\dfrac{mL\lambda}{d}$ and

$y_{m+1}=\dfrac{(m+1)L\lambda}{d}$

hence,

$\Delta y = y_{m+1} - y_m$

$\Delta y =\dfrac{L\lambda}{d}$

$\Delta y =\dfrac{5 \times 600 \times 10^{-9}}{0.02 \times 10^{-3}}$

$\Delta y =0.15\ m$

$\Delta y =15\ cm$

hence, the correct answer is option D

4 0

4 years ago

A 2000 kg truck is traveling at 25 m/s. Determine the impulse needed

Vitek1552 [10]

Answer:

A 7kg impulse

Explanation:

i think sorry if not

3 0

3 years ago

A flywheel with a radius of 0.200m starts from rest and accelerates with a constant angular acceleration of 0.900rad/s2.

kobusy [5.1K]

Answer:

The magnitude of the radial acceleration is 0.754 rad/s²

Explanation:

Given;

radius of the flywheel, r = 0.2 m

initial angular velocity of the flywheel, $\omega_i = 0$

angular acceleration of the flywheel, a = 0.900 rad/s².

angular distance, θ = 120⁰

the angular distance in radian = $\frac{120}{180} \pi = \frac{2 \pi}{3} \ rad$

Apply the following kinematic equation to determine the final angular velocity;

$\omega _f^2 = \omega _i ^2 + 2\alpha \theta\\\\\omega _f^2 = 0 + 2(0.9)(\frac{2\pi}{3} )\\\\\omega _f^2 = 3.7699\\\\\omega _f = \sqrt{ 3.7699} \\\\ \omega _f = 1.942 \ rad/s$