Answer:
Total energy saving will be 0.8 KWH
Explanation:
We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW
30 bulbs are of power 60 W
So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW
Total power of 80 bulbs = 1.8+5 = 6.8 KW
Total time = 3 hour
We know that energy ![E=power\times time=6.8\times 3=20.4KWH](https://tex.z-dn.net/?f=E%3Dpower%5Ctimes%20time%3D6.8%5Ctimes%203%3D20.4KWH)
Now power of each CFL bulb = 25 W
So power of 80 bulbs = 80×25 = 2000 W = 2 KW
Energy of 80 bulbs = 2×3 = 6 KWH
So total energy saving = 6.8-6 = 0.8 KWH
Nuclear Fission s a power source with a very low environmental impact.
The startling answer is:
The bacteria ate the agar and reproduced (made more bacteria). There are so many of them now that you can see the blob of them.
Answer:
correct answer is b Z --->Z+1
Explanation:
In the processes of radioactive decay there are three basic processes the emission of alpha particles and the emission of beta rays and the emission of ayos range
The emission of a beta ray implies the transformation of a neutral into a proton, which implies the increase of the atomic number in a unit
Z ----> Z +1
the atomic mass does not change since the mass of the two particles is practically the same, to balance the reaction antineutrino must also be emitted
The daughter particle is in an execrated state and passes to its base state with the emission of a gamma ray that does not change its atomic number or its atomic mass.
Consequently, from the above the correct answer is b
Answer:
n = 1.89 x 10¹⁹ photons/s
Explanation:
given,
Power of bulb = 100 W
Visible light = 5 W
wavelength of the visible light = 600 nm
number of photons emitted per second
using formula of wavelength
![\lambda = \dfrac{c}{\nu}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cdfrac%7Bc%7D%7B%5Cnu%7D)
![\nu= \dfrac{c}{\lambda}](https://tex.z-dn.net/?f=%5Cnu%3D%20%5Cdfrac%7Bc%7D%7B%5Clambda%7D)
![\nu= \dfrac{3 \times 10^8}{600 \times 10^{-9}}](https://tex.z-dn.net/?f=%5Cnu%3D%20%5Cdfrac%7B3%20%5Ctimes%2010%5E8%7D%7B600%20%5Ctimes%2010%5E%7B-9%7D%7D)
![\nu=5 \times 10^{14}\ Hz](https://tex.z-dn.net/?f=%5Cnu%3D5%20%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
energy of photon
U = h υ
U = 6.63 x 10⁻³⁴ x 4 x 10¹⁴
U = 2.65 x 10⁻¹⁹ J
number of photon
![n = \dfrac{P}{U}](https://tex.z-dn.net/?f=n%20%3D%20%5Cdfrac%7BP%7D%7BU%7D)
![n = \dfrac{5}{2.65 \times 10^{-19}}](https://tex.z-dn.net/?f=n%20%3D%20%5Cdfrac%7B5%7D%7B2.65%20%5Ctimes%2010%5E%7B-19%7D%7D)
n = 1.89 x 10¹⁹ photons/s