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loris [4]
3 years ago
15

Read each scenario and then answer the question. Scenario A: A 6-kg bucket is raised a distance of 6 m. Scenario B: A 9-kg bucke

t is raised a distance of 5 m. Scenario C: A 12-kg bucket is raised a distance of 4 m. Scenario D: A 15-kg bucket is raised a distance of 3 m. Which scenario generates the most gravitational potential energy?

Physics
2 answers:
OLEGan [10]3 years ago
8 0

Explanation:

It's <u><em>C cccccccccccccccccccccccccccccccccccccccccccccccccccccccc</em></u>

MAXImum [283]3 years ago
6 0

Answer:

Scenario C: A 12-kg bucket is raised a distance of 4 m.

Explanation:

I just took the quiz and that's the correct answer

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A substance did not change it's chemical nature in reaction which mostly likely describe the reaction
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If the substance doesn't change chemically, it is a physical reaction.
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3 years ago
1. Calculate the charge in a circuit which carries a current of 30 amperes for 5 seconds
sweet-ann [11.9K]

Answer:

1. 150C.

2. 50sec

3.1.5a

Explanation:

1. I = Q/T

Q= 30x5

=150c

2.applying the formulae, I = Q/T

T= Q/I

=500/10

=50sec.

3. using the formulae i=q/t

i= 120/80

=1.5a.

6 0
3 years ago
A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c
Delvig [45]

Answer:

E=\dfrac{\lambda }{2\pi \varepsilon _or}

Explanation:

Given that

For straight wire

Charge density= λ

For hollow metal cylinder

Charge density=2 λ

We know that electric filed for wire given as

E_w=\dfrac{\lambda_{wire} }{2\pi \varepsilon _or}

E_w=\dfrac{\lambda }{2\pi \varepsilon _or}

Now the electric filed due to hollow metal cylinder

E_c=\dfrac{\lambda_{cylinder} }{2\pi \varepsilon _or}

E_c=\dfrac{2\lambda }{2\pi \varepsilon _or}

Now  by considering the Gaussian surface r<R then only electric fild due to wire will present.So

At r<R

E=\dfrac{\lambda }{2\pi \varepsilon _or}

5 0
4 years ago
if you have a kinetic energy of 1470 J, and you are 60kg mass and 0 m above the ground, what is you velocity?
laiz [17]

Answer:

The 39.

Explanation:

8 0
2 years ago
Read 2 more answers
A pendulum is raised to a height of 0.3m above its lowest point and released. What is the velocity of the pendulum at its lowest
enyata [817]

Answer:

v = 2,425 m / s

Explanation:

A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.

highest point

           Em₀ = U = m g y

lowest point

          Em_{f} = K = ½ m v²

         Em₀ = Em_{f}

        mg y = ½ m v²

        v = √ 2gy

let's calculate

        v = √ (2 9.8 0.3)

        v = 2,425 m / s

3 0
3 years ago
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