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MAXImum [283]
4 years ago
15

when an element tends to lose its valence electrons in chemical reactions , does it behave more like a metal or nonmetal

Physics
1 answer:
Juli2301 [7.4K]4 years ago
4 0

It behaves more like a metal

Explanation:

When an element tends to lose its valence electrons in chemical reactions, they behave more like a metal.

Metals are electropositive.

Electropositivity or metallicity is the a measure of the tendency of atoms of an element to lose electrons.

This is closely related to ionization energy and the electronegativity of the element.

  • The lower the ionization energy of an element, the more electropositive or metallic the element is .

Metals are usually large size and prefers to be in reactions where they can easily lose their valence electrons.

When most metals lose their valence electrons, they attain stability.

Non-metals are electronegative. They prefer to gain electrons.

learn more:

Reactivity brainly.com/question/6496202

#learnwithBrainly

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natita [175]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

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4 0
3 years ago
A bat with a mass of 0.35 kg travels at a rate of 15 m/s. What is the animal's momentum?
Tanya [424]

Answer:

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6 0
3 years ago
Pendulum A has a bob of mass m hung from the string of length L; pendulum B is identical to A except its bob has the length 2L.
GenaCL600 [577]

Answer:

f_{B}: f_{A} = \sqrt{\frac{2}{1}}

Explanation:

For pendulum A: Length = L and gravity = g

The frequency of pendulum A is given by

f = \frac{1}{2\pi }\sqrt{\frac{g}{L}}

Here, f is the frequency, L be the length

f_{A} = \frac{1}{2\pi }\sqrt{\frac{g}{L}}     ... (1)

For pendulum B: Length = 2L, gravity = g

The frequency of pendulum B is given by

f_{B} = \frac{1}{2\pi }\sqrt{\frac{g}{2L}}   .... (2)

Divide equation (1) by (2)

f_{B}: f_{A} = \sqrt{\frac{2}{1}}

5 0
3 years ago
Answers please!! i have to give it up in 2 hours!!
aleksklad [387]

Answer:

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3 0
3 years ago
10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
Mila [183]

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

   = 0.25 cm

The wire is 0.25 cm thick.

8 0
3 years ago
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