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Ganezh [65]
3 years ago
8

How does a higher heat capacity affect the amount of time it takes for an object’s temperature to change?

Physics
1 answer:
Alenkasestr [34]3 years ago
8 0
higher~ specific ~heat  ~capacity  ~means ~ it  ~has  ~higher  ~heat ~  energystorage



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What is the kinetic energy of a 200 kg satellite as it follows a circular orbit of radius 8x106m around the earth?
motikmotik
Given the equation for the Speed of a Satellite

v = SqRt{Gravitational Constant}{Mass of Earth} divided by the radius given in your problem

we have:


(square root whole term on right side)

v = G Me
———
r


so. (6.67x10^-11)(5.97x10^24)
___________________
(8.0x10^6)


v = 7055 m/s (which is reasonable)


so utilize the Kinetic Energy Formula


KE = 1/2mv^2


KE = 1/2(200)(7055)^2


KE = 4.977x10^9 J


4 0
3 years ago
Read 2 more answers
A rubber band has potential energy of 5 J. If the spring constant of the rubber band is 50 N/m, what is the displacement of the
Valentin [98]
To determine the displacement, since we are given the potential energy, we use the equation for potential energy. For a spring, it is one-half the product of the spring constant and the square of the displacement. We do as follows:

PE = kx^2/2
5 Nm = 50N/m (x^2)
x = 0.32 m

Therefore, the displacement would be 0.32 m.
7 0
4 years ago
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Which component measures the potential difference across a branch in a circuit? A. switch B. resistor C. ammeter D. voltmeter
NNADVOKAT [17]

Answer:

Voltmeter

Explanation:

7 0
3 years ago
A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i
nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

U=mgh

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

U=mgh

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J

3. 0 J

As before, the gravitational potential energy of the ball is given by

U=mgh

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J

4 0
3 years ago
What type of electromagnetic radiation is being used in the picture?
pashok25 [27]

Answer: b i think

Explanation:

6 0
3 years ago
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