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Butoxors [25]
3 years ago
8

For a molecule of fluorous acid, the atoms are arranged as HOFO. (Note: In this oxyacid, the placement of fluorine is an excepti

on to the rule of putting the more electronegative atom in a terminal position.)What is the formal charge on each of the atoms? Enter the formal charges in the same order as the atoms are listed.Express your answers as charges separated by comma. For example, a positive one charge would be written as +1.Formal Charge for H, O, F, O =_______.
Chemistry
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:

0,0,0,0

Explanation:

The formal charge formula:

Formal charge= Valence electrons - lone pair electrons - 0.5 shared electrons

So:

Hydrogen: 1 elec. of valence and shares two electrons with the O

Formal charge= 1 - 0 - 0.5*2=0

Oxygen: 6 elec. of valence, 2 lone pairs and shares two electrons with the H and two with the F

Formal charge= 6 - 4 - 0.5*4=0

Fluorine: 7 elec. of valence, 6 lone pairs and shares two electrons with the O

Formal charge= 7 - 6 - 0.5*2=0

Oxygen: 6 elec. of valence, 3 lone pairs

Formal charge= 6 - 6 - 0.5*0=0

Note: the dative bond between F and the second O doesn't count as shared electrons.

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Read 2 more answers
The ammonia molecule NH3 has a permanent electric dipole moment equal to 1.47 D, where 1 D = 1 debye unit = 3.34 × 10-30 C-m. Ca
svetoff [14.1K]

The electric potential due to ammonia at a point away along the axis of a dipole is 1.44 \times 10^-5 V.

<u>Explanation:</u>

Given that 1 D = 1 debye unit = 3.34 × 10-30 C-m.

Given p = 1.47 D = 1.47 \times 3.34 \times 10^-30 = 4.90 \times 10^-30.

            V = 1 / (4π∈о)  \times  (p cos(θ)) / (r^2)

where p is a permanent electric dipole,

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            V is the electric potential.

        V = 1 / (4 \times 3.14 \times 8.85 \times 10^-12)  \times (4.90 \times 10^-30 \times 1) / (55.3 \times 10^-9)^2

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