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Liula [17]
3 years ago
10

Which of the following was a cause of the French and Indian War?

Chemistry
2 answers:
noname [10]3 years ago
5 0

Answer:

The cause of the French and Indian War was that Britain and France disputed borders in the Ohio River Valley.

Explanation:

The French and Indian War was a war between the Kingdom of Great Britain and the Kingdom of France in North America from 1754 to 1763. It all started as a territorial conflict in the North American colonies of these two colonial powers.

In 1756, the war expanded to the world and became part of the Seven Years' War. The Indians formed an alliance with France in this war and attacked Britain. The Battle of Signal Hill in September 1762 established the British control of French Canada and the war ended. In the same year, France secretly signed the Fontainebleau Treaty and ceded French Louisiana to Spain. On February 10, 1763, the British and French signed the Paris Treaty. Spain ceded Florida to the United Kingdom, and France ceded the territories to the east of the Mississippi River in Louisiana to the United Kingdom. This war was a turning point for French forces in North America and confirmed the UK's control position in the eastern half of the continent.

Hitman42 [59]3 years ago
3 0

Answer:

Britain and France disputed borders in the Ohio River Valley

the war which took place between 1754-1763, began due to a conflict between England and France over control of the Ohio River Valley. Both sides wanted the valley so they could expand their settlements into the area.

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<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})
  2. Multiply/Divide:                                                                                                \displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

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