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olganol [36]
3 years ago
9

Which reaction takes place in a nuclear fission reactor

Chemistry
2 answers:
BlackZzzverrR [31]3 years ago
6 0

Answer:c

Explanation:

edg

cluponka [151]3 years ago
5 0
Fission. When a large fissile atomic nucleus such as uranium-235 or plutonium-239 absorbs a neutron, it may undergo nuclear fission. The heavy nucleus splits into two or more lighter nuclei, (the fission products), releasing kinetic energy, gamma radiation, and free neutrons.
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Hi i need help. Select all the statements that are true.
motikmotik

Answer:

A, C, E

Explanation:

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7 0
3 years ago
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A 25 liter balloon holding 1.5 moles of carbon dioxide leaks. If we are able to determine that 0.9 moles of carbon dioxide escap
ad-work [718]

Answer:

10 Litre

Explanation:

Given that ::

v1 = 25L ; n1 = 1.5 mole ; v2 =? ; n2 = (1.5-0.9) = 0.6 mole

Using the relation :

(n2 * v1) / n1 = (n2 * v2) / n2

v2 = (n2 * v1) / n1

v2 = (0.6 mole * 25 Litre) / 1.5 mole

v2 = 15 / 1.5 litre

v2 = 10 Litre

3 0
2 years ago
What is the volume of 2.268mol of oxygen gas at 35○C and 3.0atm?
Eduardwww [97]
The volume is 

3 x_{123}
6 0
3 years ago
Why is the air in a jet aircraft flying at high altitudes pressurized? *
saw5 [17]

Answer:

Aircraft cabins are therefore pressurized to maintained a similar pressure as that experienced at sea level to ensure normal breathing of passengers.

Explanation:

-Air becomes increasingly thinner with increasing altitudes.

-As such, oxygen becomes limited at higher altitudes and makes it difficult or almost impossible to breath  a condition called hypoxia.

-Aircraft cabins are therefore pressurized to maintained a similar pressure as that experienced at sea level to ensure normal breathing of passengers.

6 0
3 years ago
Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A 100-mL graduated cylinder w
kicyunya [14]

Answer:

h=100.8cm

Explanation:

Hello,

In this case, considering the density and mass of both water and heptane we first compute the volume of each one:

V_{water}=\frac{m_{water}}{\rho _{water}}=\frac{34g}{1.00g/mL}=34mL\\  \\V_{heptane}=\frac{m_{heptane}}{\rho _{heptane}}=\frac{34.6g}{0.684g/mL}=50.6mL\\

Now, the total volume is:

V=50.6mL+34mL=84.6mL

Which is equal to:

V=84.6cm^3

Then, by knowing that the volume of a cylinder is πr²h or π(D/2)²h, we solve for the height as follows:

h=\frac{V}{\pi (D/2)^2} \\\\h=\frac{84.6cm^3}{\pi (3.16cm/2)^2} \\\\h=100.8cm

Best regards.

3 0
3 years ago
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