I hope this is what you are looking for
P1 = 270 kPa
V1 = 1 L
P2 = 540 kPa
V2 = ?
Use Boyle's Law:
P1V1 = P2V2
V2 = P1 V1 / P2
V2 = 270 x 1 / 540
V2 = 0.5 L
The churning air in the troposphere helps determine the altitude of a place
Particles can either have a positive or negative charge.
Answer:
The power she can generate is 185.22 KW.
Explanation:
<h3><u>DATA</u></h3>
3.00m wide and 0.500m deep.
Cross sectional area = 1.500m^2
Velocity = 1.35m/s
Volumetric flow rate = Av = 18.00m^3/s
Mass flow rate = 18,000kg/s
Height = 4.20m
25.0% efficiency
<h3><u>
FORMULA:</u></h3>
P = dE / dt * eff
<h3><u>
SOLUTION:</u></h3>
18,000kg/s (9.8m/s^2) (4.20m) (25%) = 185,220 watts
= 185 kw
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
We know from the Coulomb's Law that, Coulomb's force is directly proportional to the product of two charges q1 and q2 and inversely proportional to the square of the radius between them.
So,
F = 
Now, we are asked to get the greatest force. So, in order to do that, product of the charges must be greatest because the force and product of charges are directly proportional.
Let's suppose, q1 = q
So,
if q1 = q
then
q2 = Q-q
Product of Charges = q1 x q2
Now, it is:
Product of Charges = q x (Q-q)
So,
Product of Charges = qQ - 
And the expression qQ -
is clearly a quadratic expression. And clearly its roots are 0 and Q.
So, the highest value of the quadratic equation will be surely at mid-point between the two roots 0 and Q.
So, the midpoint is:
q =
q = Q/2 and it is the highest value of each charge in order to get the greatest force.