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alexira [117]
4 years ago
5

Bob is pulling a 30 kg filing cabinet with a force of 200 N , but the filing cabinet refuses to move. The coefficient of static

friction between the filing cabinet and the floor is 0.80. What is the magnitude of the friction force on the filing cabinet?
Physics
1 answer:
Arada [10]4 years ago
5 0

Answer:

<em>Magnitude of the Frictional force is 200 N</em>

Explanation:

The frictional force is the force that tries to oppose relative motion between two surfaces that are contacting. The coefficient of static friction is the coefficient of friction of a body that is not moving.

Newton's third law of motion states that action and reaction forces are equal and opposite. So the frictional force felt on the filing cabinet will be equal to the applied force pulling the cabinet.

Frictional force = Force applied

Force applied  = 200 N

Therefore, the magnitude of the friction force on the filing cabinet is 200 N

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A cart is moving at 55 m/s at an angle of 25° to the ground. Determine the horizontal component.
Elodia [21]

Answer:

<em>The horizontal component of the velocity is 49.85 m/s.</em>

Explanation:

<u>Rectangular Components of a Vector</u>

A 2D vector can be expressed in several forms. The rectangular form gives its two components, one for each axis (x,y). The polar form gives the components as the pair (r,θ) being r the magnitude and θ the angle.

When the magnitude and angle of the vector are given, the rectangular components are calculated as follows:

v_x=v\cos\theta

v_y=v\sin\theta

Where v is the magnitude of the vector and θ is the angle with respect to the x positive direction.

The cart is moving at v=55 m/s at θ=25°, thus:

v_x=55\cos 25^\circ

v_x=49.85\ m/s

The horizontal component of the velocity is 49.85 m/s.

7 0
3 years ago
A woman starts to swim directly across a 5.2-km-wide river. Her speed with respect to the water is 1.9 m/s. The river current ca
elena-14-01-66 [18.8K]

Answer:

(a) the time needs for her to cross the river is 2736.8 s.

(b) the distance takes to reach the other side of the river is 2490.5 m.

Explanation:

given information:

woman's speed, v₁ = 1.9 m/s

the wide of river, s = 5.2 km = 5200 m

river's current, v₂ = 0.91 m/s

(a) How much time does it take her to cross the river?

s = v t

s = the displacement (m)

v = speed (m/s)

t = time (s)

s = v t

t = s/v

 = 5200/1.9

 = 2736.8 s

(b) How far downstream will the river carry her by the time she reaches the other side of the river?

s = v t

  = (0.91) (2736.8)

  = 2490.5 m

8 0
3 years ago
until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track , it can speed up to
kiruha [24]

Answer:

5

Explanation:

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3 years ago
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mestny [16]
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Withdrawal symptoms are the complete opposite, leading to a dependency on the drug which causes far more damage than the effects of the drug itself.
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2. If you want to increase the pressure, you should increase the area over which the force operates. True False
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P=F/A, you're dividing by A. If you say, doubled A, you'd have only half the pressure.
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