Probably ocean currents since these use heat to move large amounts of water throughout the ocean, and can you make this the brainliest answer
Answer:
1.41 m/s^2
Explanation:
First of all, let's convert the two speeds from km/h to m/s:


Now we find the centripetal acceleration which is given by

where
v = 12.8 m/s is the speed
r = 140 m is the radius of the curve
Substituting values, we find

we also have a tangential acceleration, which is given by

where
t = 17.0 s
Substituting values,

The two components of the acceleration are perpendicular to each other, so we can find the resultant acceleration by using Pythagorean theorem:

Answer:
D lower energy waves is most likely the safest if one is exposed to.
Answer:
(i) W = 8.918 N
(ii) 
(iii) d = 9.1 cm
Explanation:
Part a)
As we know that weight of cube is given as


here we know that



now the mass of the ice cube is given as

now weight is given as

Part b)
Weight of the liquid displaced must be equal to weight of the ice cube
Because as we know that force of buoyancy = weight of the of the liquid displaced

So here volume displaced is given as



Part c)
Let the cube is submerged by distance "d" inside water
So here displaced water weight is given as



so it is submerged by d = 9.1 cm inside water