Ice wedging, pressure release, plant root growth, and abrasion can<span> all </span>break<span> apart</span>rocks<span>. ... When plants grow in cracks in a </span>rock<span>, their roots </span>can<span> widen the cracks and force the </span>rock<span> apart. Rainwater fills small cracks in a </span>rock<span>. As the </span>water<span> freezes, it expands, widening the cracks and splitting apart the </span>rock<span>.</span>
Answer:how long it took him to get there
Explanation:
Incomplete question as we have not told which quantity to find.So the complete question is here
A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.Given this, how large a current does it carry?
Answer:
Explanation:
Magnetic field B=1.5 T
Length L=2.2mm =0.0022m
Number of turns N=1300 turns
To find
Current I
Solution
From the magnetic at the center of loop we know that:
Substitute the given values
For answering this question,let us assume that a person is pushing against the walls,so now:
Which object exerts the action force?
Which object exerts the reaction force?
In what direction does the action force push?
In what direction does the reaction force push?
The answer varies from different scenarios.
Answer:
r₂ = 1,586 m
Explanation:
For this problem we are going to solve it by parts, let's start by finding the sound intensity when we are 25 m
β = 10 log (I / I₀)
where Io is the sensitivity threshold 10⁻¹² W / m²
I₁ / I₀ =
I₁ = I₀ e^{\beta/10}
let's calculate
I₁ = 10⁻¹² e^{25/10}
I₁ = 1.20 10⁻¹¹ W / m²
the other intensity in exercise is
I₂ = 10⁻¹² e^{80/10}
I₂ = 2.98 10⁻⁹ W / m²
now we use the definition of sound intensity
I = P / A
where P is the emitted power that is a constant and A the area of the sphere where the sound is distributed
P = I A
the area a sphere is
A = 4π r²
we can write this equation for two points of the found intensities
I₁ A₁ = I₂ A₂
where index 1 corresponds to 25m and index 2 to the other distance
I₁ 4π r₁² = I₂ 4π r₂²
I₁ r₁² = I₂ r₂²
r₂ = √ (I₁ / I₂) r₁
let's calculate
r₂ = √ (1.20 10⁻¹¹ / 2.98 10⁻⁹) 25
r₂ = √ (0.40268 10⁻²) 25
r₂ = 1,586 m