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lara [203]
3 years ago
6

(URGENT 75 points)You are given two same party balloons (one filled with helium and the

Physics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

you have to substitiute volume of the ballon

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An object that has a small mass and an object that has a large mass have the same momentum. which object has the largest kinetic
castortr0y [4]
The larger mass object would have more kinetic energy. 1) its heavier 2) it covers a larger area 3) the more mass an object has, the larger the kinetic energy because of its weight.
6 0
3 years ago
What is the current in a 160V circuit if the resistance is 20Ω
Mkey [24]

Answer:

I =V/R

I= 160/20 = 8 Amperes

3 0
3 years ago
A cylindrical can 150 mm in diameter is filled to a depth of 100 mm with a fuel oil. The oil has a mass of 1.56 kg. Calculate it
Kazeer [188]

Answer:

Density (φ) = 0,8827 Kg/L

Specific weight (Ws) = 8,65 N/L

Specific gravity (Gs) = 0,8827 (without unit)

Explanation:

The density formula: φ = \frac{m}{V}

I know the mass "m", I need to find out the volume of the cylinder (V)

V = π* r²*h

The radius "r" is equal to half the diameter (150mm) = 75mm

Now I can find out the density (φ)

φ = \frac{1,56Kg}{1,767145L} = 0,8827 Kg/L

The specific weight (Ws) is the relationship between the weight of substance (oil) and its volume. We apply the following formula:

Ws = φ*g

(g = gravity = 9,8 m/s²)

Finally, specific gravity (Gs) is the ratio between the density of a substance (oil) "φ(o)" and the density of water "φ(w)" :

Gs = φ(o) /  φ(w)

(φ(w) = 1 Kg/L

Hope this can help you !!

3 0
3 years ago
If the tension of the cable is 25.0 N what is the mass of the ball
marysya [2.9K]

Answer:576

Explanation:

5 0
3 years ago
State the term used to describe the turning force exerted by the man
ozzi

]A force called the effort force is applied at one point on the lever in order to move an object, known as the resistance force, located at some other point on the lever.

The way levers work is by multiplying the effort exerted by the user. Specifically, to lift and balance an object, the effort force the user applies multiplied by its distance to the fulcrum must equal the load force multiplied by its distance to the fulcrum. Consequently, the greater the distance between the effort force and the fulcrum, the heavier a load can be lifted with the same effort force.

8 0
2 years ago
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