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lara [203]
4 years ago
6

(URGENT 75 points)You are given two same party balloons (one filled with helium and the

Physics
1 answer:
Ira Lisetskai [31]4 years ago
4 0

you have to substitiute volume of the ballon

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A plane travels at an average speed of 600 kilometers per hour. How long
sdas [7]

Answer:

12 mins

Explanation:

120km/600km = 1/5 or .2

60mins*0.2 = 12 mins

6 0
3 years ago
Anyone good in physics i need asp G10!!!!!
Gemiola [76]

Answer:

nope....sorry!

Explanation:

8 0
3 years ago
A grasshopper floating in water generates waves at a rate of three per second with a wavelength of two centimeters. (a) What is
Nastasia [14]

Answer:

(a) 0.33 second

(b) 6 cm/s

Explanation:

Frequency, f = 3 waves per second

wavelength, λ = 2 cm = 0.02 m

(a) The period of wave is defined as the time taken by the wave to complete one oscillation. It is the reciprocal of frequency.

T = 1 / f = 1 / 3 = 0.33 second

(b) the relation between wave velocity, frequency and wavelength is given by

v = f x λ

v = 3 x 0.02 = 0.06 m /s

v = 6 cm /s

8 0
3 years ago
Water is flowing through a channel that is 12m wide with a
Alexus [3.1K]

Answer:

Velocity from second channel will be 1.6875 m/sec

Explanation:

We have given width of the channel , that is diameter of the channel 1 d_1 = 12 m

So radius r_1=\frac{d_1}{2}=\frac{12}{2}=6m

Speed through the channel 1 v_1=0.75m/sec

Width , that is diameter of the channel 2 d_2=4m

So r_2=2m

From continuity equation

A_1v_1=A_2v_2

\pi \times 12^2\times 0.75=4\times \pi\times  4^2\times v_2

v_2=1.6875m/sec

So velocity from smaller channel will be 1.6875 m /sec

6 0
3 years ago
An electric heater supplies 5kw of power to atank of water assume all the energy supplied is converted into heat energy and the
kicyunya [14]

Answer:

<em>8hours 45minutes</em>

Explanation:

Amount of heat energy used up by the electric substance = heat gained by the water.

Amount of heat energy used up by the electric substance = Power * Time

heat gained by the water. = mcΔt

m is the mass of the water in kg

c is the specific heat capacity

Δt is the change in temperature

Given parameters

Power = 5kW = 5000W

mass of water m = 500kg

c = 4200J/kgC

Δt = 100°C - 25°C = 75°C

Required

Time taken

Substituting the given parameters into the formula

Pt = mcΔt

5000t = 500*4200*75

5000t = 157,500,000

Divide both sides by 5000

t =  157,500,000/5000

t = 31,500 secs

t = (31,500/3600)hrs

t = 8.75hours

t = 8hours 45minutes

<em>Hence it takes 8hours 45minutes to heat 500 kg of water in the tank from 25c to 100c</em>

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6 0
4 years ago
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