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2 years ago

Mitchell records the amount of time a toy car takes to travel down a ramp one time for each of four slope angles. His lab

Physics

1 answer:

Alexandra [31]2 years ago

4 0

He should run the same set of trials more times in order to improve the precision of the result

Explanation:

When doing a scientific experiment, the results of the measurement are subjected to errors. There are various types of errors:

- Statistical errors: these are due to the limited precision of the instruments used for the measurement. For example, when measuring a lenght with a ruler, the ruler cannot measure with a precision of less than 1 mm, so we always have at least an uncertainty of 1 mm on the measurement done

- Systematic errors: these are errors due to faulty equipment of flaws in the design of the experiment.

In order to reduce the statistical error, it is important to repeat the same measurement more than once: in this way, we can calculate an average for the quantity we are measuring, and the uncertainty on the measure will be reduced.

In this problem, therefore, the amount of time taken by the toy car to travel down the ramp must be measured more times, and then Mitchell should calculate an average for each set of trials, in order to improve the precision of the results.

Learn more about errors here:

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Two square air-filled parallel plates that are initially uncharged are separated by 1.2 mm, and each of them has an area of 190

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Answer:

$5.5\cdot 10^{-11} C$

Explanation:

The capacitance of the parallel-plate capacitor is given by:

$C=\epsilon_0 \frac{A}{d}$

where

$\epsilon_0 = 8.85\cdot 10^{-12} F/m$ is the vacuum permittivity

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$d=1.2 mm = 0.0012 m$ is the separation between the plates

Substituting,

$C=(8.85\cdot 10^{-12}) \frac{190 \cdot 10^{-6}}{0.0012}=1.4\cdot 10^{-12}F$

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$U=\frac{Q^2}{2C}$

Since we know the energy

$U=1.1 nJ = 1.1 \cdot 10^{-9} J$

we can re-arrange the formula to find the charge, Q:

$Q=\sqrt{2UC}=\sqrt{2(1.1\cdot 10^{-9} J)(1.4\cdot 10^{-12}F )}=5.5\cdot 10^{-11} C$

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5. A single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen. The 5th minimum occurs at 7.00° aw

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theta=25.3

Option A is correct

<h3> What angle does the 18th minimum occur?</h3>

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