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2 years ago

Two dimensional motion is motion in :

Physics

1 answer:

ExtremeBDS [4]2 years ago

4 0

Answer:

Explanation:

Motion in the X and the Y axis

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In which regions can the gravitational field strength due to the two planets be zero? Explain.

yan [13]

Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

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3 years ago

Bandura found that children who witnessed aggressive behavior being punished were far more likely to be aggressive than children

Sonbull [250]

Answer:

The evidence is conclusive; aggression and violence in the media lead to aggression and violence in the general population.

Explanation:

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1 year ago

Which phenomenon would cease to exist in the absence of this axial tilt?

konstantin123 [22]

If the Earth didn't tilt then we wouldn't have seasons.

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2 years ago

An elephant and a mouse would both have zero weight in gravity-free space. If they were moving toward you with the same speed, w

Dovator [93]

The elephant and the mouse having zero weight in a gravity free space will not bump into you at the same effect.

<u>Explanation: </u>

When both are in a gravity free space, the weights are zero, as we know that the $\text {weight of the body}=\text {mass of the body} \times \text {acceleration due to gravity}$

$\text {here, the weight of elephant}=\text {mass of elephant } \times \text {zero gravti} y=zero$

$\text {similarly,weight of mouse}=\text {mass of mouse } \times \text {zero gravity}=zero$

But when they will acquire the speed of same magnitude, say v, their different masses will acquire different momentum, which will make the difference in effect while bumping.

$\text { momentum of elephant }=\text { mass of elephant } \times v$ $\text { momentum of mouse = mass of mouse } \times v$

And as we know $\text { mass of elephant }>\text { mass of mouse }$ Therefore, effect of impact by elephant will be more than that of mouse . An elephant breaking into you will take you back faster than a mouse in space hits you.

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2 years ago

PART ONE

Lina20 [59]

Explanation:

Make a table, listing the x and y coordinates of each square's center of gravity and its mass. Multiply the coordinates by the mass, add the results for each x and y, then divide by the total mass.

$\left\begin{array}{ccccc}x&y&m&xm&ym\\\frac{a}{2} &\frac{a}{2} &10&5a&5a\\\frac{3a}{2}&\frac{a}{2}&70&105a&35a\\\frac{a}{2}&\frac{3a}{2}&80&40a&120a\\\frac{3a}{2}&\frac{3a}{2}&50&75a&75a\\&\sum&210&225a&235a\\&&Avg&\frac{15a}{14}&\frac{47a}{42}\end{array}\right$

The x-coordinate of the center of gravity is 15/14 a.

The y-coordinate of the center of gravity is 47/42 a.

4 0

3 years ago