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ad-work [718]
3 years ago
14

FILL IN THE BLANK an elements __________ is its row in the periodic table

Chemistry
2 answers:
Kipish [7]3 years ago
6 0

elements are classified into rows and columns in the periodic table.

Elements are arranged in the increasing order of the atomic number

elements with same number of valence electrons fall into the same column. these columns are called groups.

elements having the same amount of outermost energy shells fall into the same row. These rows are called periods.

therefore elements where the highest energy electron is in the second energy shell belongs to period 2

and elements with highest energy electron is the third energy shell belongs to period 3 and so on.

Therefore rows represent the periods of elements


answer is an elements period is its row in the periodic table

Sedaia [141]3 years ago
3 0
The question is asking to complete the said statement that is all about the element in the periodic table and base on my research and further investigation, I would say that the answer would be a Period. I hope you are satisfied with my answer and feel free to ask for more 
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Class material don't interact please
bagirrra123 [75]

A 0.00143 M  concentration of MnO4^- is not a reasonable solution .

<h3>Number of moles of carbonate</h3>

The ions left in solution are Na^+ and NO3^-

Number of moles of calcium nitrate  = 100/1000 L × 1 = 0.1 moles

Since;

1 mole of sodium carbonate reacts with 1 mole of calcium nitrate  then 0.1 moles of sodium carbonate were used.

<h3>Conductivity of filtrate</h3>

The claim of the student that the concentration of sodium carbonate is too low is wrong because the value was calculated from concentration  and volume of calcium nitrate  and not using the precipitate. If the filtrate is tested for conductivity, it will be found to conduct electricity because it contains sodium and NO3 ions.

2) In the reaction as shown, the MnO4^- ion was reduced.

The initial volume is 3.4 mL while the final volume is 29.6 mL.

Number of moles of MnO4^- ion = (29.6 mL - 3.4 mL)/1000 × 0.0235 M = 0.0006157 moles

<h3>The calculations are performed as follows</h3>

  • If 2 moles of MnO4^- reacted with 5 moles of acid

0.0006157 moles of MnO4^- reacted with  0.0006157 moles ×  5 moles/ 2 moles

= 0.0015 moles

  • In this case, number of moles of acid = 0.139 g/90 g/mol = 0.0015 moles

Number of moles of MnO4^-  = 0.00143 M × (29.6 mL - 3.4 mL)/1000

= 0.000037 moles

  • If 2 moles of MnO4^- reacts with 5 moles of acid

0.000037 moles of MnO4^- reacts with 0.000037 moles × 5 moles/ 2 moles

= 0.000093 moles

  • Hence, this is not a reasonable amount of solution.

Learn more about MnO4^- : brainly.com/question/10887629

8 0
2 years ago
1.Which of the following are considered pure substances
PilotLPTM [1.2K]
1.) homogeneous mixtures

2.) <span>NaCI, because sodium is a metal and chlorine is a nonmetal</span>

3.) I'm thinking the first the option 
5 0
3 years ago
What gas law applies to aerosol cans being stored in a cool place?
svetlana [45]
Don't really know if this is what your asking but P1/T1= P2/T2 should show how the pressure varies with temperature (V is left out because it's constant since the gas is trapped in an aerosol can). As the temperature rises the pressure rises and if it gets too high then the can explodes, which is why it should be stored in a cool place. There's also PV=nRT might be kind of hard to find moles (n) though.


3 0
3 years ago
Which metal is most likely to form more than one kind of positively charged ion? sodium (Na) barium (Ba) nickel (Ni) magnesium (
Naya [18.7K]
Nickel most likely will, it's a transition metal
5 0
3 years ago
Read 2 more answers
A balloon originally had a volume of 4.39 L at 44C and a pressure of 729 torr  to what temperature must the balloon be cooled
VMariaS [17]

The new temperature : 11.56 °C

<h3>Further explanation </h3>

Boyle's law and Gay Lussac's law  

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

P1 = initial gas pressure (N/m² or Pa)  

V1 = initial gas volume (m³)  

P2 = final gas pressure  

V2 = final gas volume

T1 = initial gas temperature (K)  

T2 = final gas temperature  

V₁=4.39 L

T₁=44+273=317 K

P₁ = 729 torr = 0,959211 atm

V₂=3.78 L

P₂= 1 atm

\tt \dfrac{0.959211\times 4.39}{317}=\dfrac{1\times 3.78}{T_2}\\\\T_2=\dfrac{1\times 3.78\times 317}{0.959211\times 4.39}\\\\T_2=284.559~K=11.56~C

3 0
3 years ago
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