Solute particles moving from higher concentration to lower concentration through a semi-permeable membrane is a process known as
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Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.
Explanation:
Given: Current = 62.0 A
Time = 23.0 sec
Formula used to calculate charge is as follows.
where,
Q = charge
I = current
t = time
Substitute the values into above formula as follows.
It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.
The oxidation state of Pb in is 2. So, moles deposited by Pb is as follows.
It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.
Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.
Answer:
The percentage deviation is %
Explanation:
From the question we are told that
The concentration is of the solution is
The true absorbance A = 0.7526
The percentage of transmittance due to stray light %
Generally Absorbance is mathematically represented as
Where T is the percentage of true transmittance
Substituting value
%
The Apparent absorbance is mathematically represented
Substituting values
= 0.7385
The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as
%
Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration is
%