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netineya [11]
3 years ago
12

Please help I can't balance and Google isn't helping

Chemistry
1 answer:
DiKsa [7]3 years ago
5 0
The first one is right and so is eight you have to add them together to see if they go together if they dont add what is missing
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What is the formula for titanium (I) dichromate?
MaRussiya [10]
The answer is TI(Cr207)2
8 0
3 years ago
Fe(NO3)2 not sure how to get the oxidation numbers of all elements
Shtirlitz [24]
You must remember that oxidation number of hydrogen in acids is always +1, oxidation number of oxygen in oxides & acids is always -2... metals has always oxidation number on plus!

group NO3 comes from HNO3...and oxidation number of whole acid group is always on minus and equal to the amount of hydrogen atoms in this acid... so oxidation number of NO3 = -1

we have 2 NO3 groups so 2*(-1) = -2 and that is the reason why oxidation number of Fe in this formula must be +2... because sum of all elements always gives 0!

Now we could count of oxidation number for nitrogen... we write HNO3 and start counting from right to left:
3*(-2) from oxygens + 1 from hydrogen = -5
so nitrogen must have +5 oxidation number... because sum all in formula must be 0.


4 0
3 years ago
How many particles are present in this diagram?
AVprozaik [17]
There are 9 particles
5 0
3 years ago
Read 2 more answers
What has a density of q
Novay_Z [31]

Answer:

  • Water has the density of 1.0g/ml
  • Anything with a density of less than 1.0/ml will float above water.
  • Alcohol would float above the water since it has a lighter density.

4 0
3 years ago
4th one<br> Mark the brainliest
ale4655 [162]

Answer:

1. The electronic configuration of X is: 1s2 2s2 sp6 3s2

2. The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

3. The formula of the compound form by X and Y is given as: XY

Explanation:

For X to loss two electrons, it means X is a group 2 element. X can be any element in group 2. The electronic configuration of X is:

1s2 2s2 sp6 3s2

To get the electronic configuration of the anion of element Y, let us find the configuration of element Y. This is done as follows:

Y receives two electrons from X to complete its octet. Therefore Y is a group 6 element. The electronic configuration of Y is given below

1s2 2s2 2p4

The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

The formula of the compound form by X and Y is given below :

X^2+ + Y^2- —> XY

Their valency will cancel out thus forming XY

4 0
3 years ago
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