How much work is done lifting a 12-m chain that is initially coiled on the ground and has a density 2 kg/m so that its top end i
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Answer:
The answer to your question is a = 0.25 m/s²
Explanation:
Data
mass = m = 400 kg
Force = F = 100 N
acceleration = a = ? m/s²
Process
To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.
Formula
F = ma
solve for a
a =
Substitution
Simplification and result
a = 0.25 m/s²