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Arturiano [62]
3 years ago
9

How much work is done lifting a 12-m chain that is initially coiled on the ground and has a density 2 kg/m so that its top end i

s 11 m above the ground? (Assume that acceleration due to gravity is g = 9.8 m/s2.)
Physics
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

2587.2 J.

Explanation:

From potential energy,

The work done to lift the chain = potential energy of the chain.

W = mgh............... Equation 1

Where W = work done to lift the chain, m = mass of the chain, g = acceleration due to gravity of the chain, h = height of the chain.

But,

m = m'd............... Equation 2

Where m' = density of the chain, d = length of the chain.

Substitute equation 2 into equation 1

W = m'dgh................ Equation 3

Given: m' = 2 kg/m, d = 12 m, h = 11 m, g = 9.8 m/s²

Substitute into equation 3

W = 2(12)(11)(9.8)

W = 2587.2 J.

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Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to the magnetic field. The electric field strength 1.5 m from the center of the circle is 7 mV/m.

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Explanation:

Given the data in the question;

Electric field E = 7 mV/m

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dB/dt = 9.33 m T/s

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