PLEASE HELP ASAP :|

1 answer:

5 0

Rub a balloon on a woolen fabric to pick up some electrons, to make the balloon negatively charged, and stick them to a wall, which would be positively charged to make them stick.

Opposites attract and when you stick a negatively charged objects to positively charged objects, they tend to stick together. When you pick up electrons, it increases the number of electrons which will make the object negatively charged.

Note: The first part of the answer is a single sentence. The problem says in a complete sentence, so just in case that you need only one sentence you can take the first part. If you can add in more than a sentence, you can put in more from the second paragraph.

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A wave is a disturbance that carries from one place to another through matter of space

krok68 [10]

There's supposed to be a blank in the statement, where the answer is supposed to be inserted.

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To answer the question, write the word "<em>energy</em>" in the blank.

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3 years ago

A __________ provides a visual summary of the improvements that a data mining project provides on a binary classification proble

babymother [125]

Answer:

Option (B)

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3 years ago

What should the Architect do to ensure Field-Level Security is enforced on a custom Visualforce page using the Standard Lead Con

OLEGan [10]

Answer:

the Architect should use {!$FieldType.lead.accessible} expression within the Visualforce page.

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3 years ago

An object has a kinetic energy of 225 j and a momentum of magnitude 28.3 kg · m/s. (a) find the speed of the object. m/s (b) fin

Irina18 [472]

A. hope this helps ;0

5 0

3 years ago

a projectile is launched at an angle of 30 degrees and lands later at the same level. if it's initial speed is 50 m/s, solve for

Mrrafil [7]

$using \: the \: formula \\ t = \frac{2u \sin( \alpha ) }{g} where \: u = initial \: speed \: \\ \alpha = angle \: of \: projection \\ g = acceleration \: due \: to \: gravity \\ \frac{2 \times 50 \times \sin(30) }{10} \\ \frac{100 \times 0.5}{10} = \frac{50}{10} = 5seconds$

Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres

3 0

3 years ago