What is an non example of Cultural diffusion

In a local bar, a customer slides an empty beer mug down the counter for a refill. the height of the counter is 1.15 m. the mug

yarga [219]

A. Let’s say the horizontal component of the velocity is vx and the vertical is vy. 
Initially at t=0 (as the mug leaves the counter) the components are v0x and v0y.
v0y = 0 since the customer slides it horizontally so applied force is in the x component only.

The equations for horizontal and vertical projectile motion are:
x = x0 + v0x t
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2

Setting the origin to be the end corner of the counter so that x0=0 and y0=0, hence:

x = v0x t

y = - 1/2 g t^2

Given value are: x=1.50m and y=-1.15m (y is negative since mug is going down)

1.50m = v0x t ----> v0x= 1.50/t

-1.15m = -(1/2) (9.81) t^2 -----> t =0.4842 s

Calculating for v0x:

v0x = 3.10 m/s

B. v0x is constant since there are no other horizontal forces so, v0x=vx=3.10m/s

vy can be calculated from the formula:

vy = v0y + at where a=-g (negative since going down)

vy = -gt = -9.81 (0.4842)

vy = -4.75 m/s

Now to get the angle below the horizontal, tan(90-Ø) = -vx/vy

tan(90-Ø )= 3.1/4.75

Ø = 56.87˚ below the horizontal

4 0

3 years ago

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Three ideal polarizing filters are stacked, with the polarizing axis of the second and third filters at 21 degrees and 61 degree

kvv77 [185]

Answer:

1

When second polarizer is removed the intensity after it passes through the stack is

$I_f_3 = 27.57 W/cm^2$

2 When third polarizer is removed the intensity after it passes through the stack is

$I_f_2 = 102.24 W/cm^2$

Explanation:

From the question we are told that

The angle of the second polarizing to the first is $\theta_2 = 21^o$

The angle of the third polarizing to the first is $\theta_3 = 61^o$

The unpolarized light after it pass through the polarizing stack $I_u = 60 W/cm^2$

Let the initial intensity of the beam of light before polarization be $I_p$

Generally when the unpolarized light passes through the first polarizing filter the intensity of light that emerges is mathematically evaluated as

$I_1 = \frac{I_p}{2}$

Now according to Malus’ law the intensity of light that would emerge from the second polarizing filter is mathematically represented as

$I_2 = I_1 cos^2 \theta_1$

$= \frac{I_p}{2} cos ^2 \theta_1$

The intensity of light that will emerge from the third filter is mathematically represented as

$I_3 = I_2 cos^2(\theta_2 - \theta_1 )$

$I_3= \frac{I_p}{2}(cos^2 \theta_1)[cos^2(\theta_2 - \theta_1)]$

making $I_p$ the subject of the formula

$I_p = \frac{2L_3}{(cos^2 \theta [cos^2 (\theta_2 - \theta_1)])}$

Note that $I_u = I_3$ as $I_3$ is the last emerging intensity of light after it has pass through the polarizing stack

Substituting values

$I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (61-21)])}$

$I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (40)])}$

$=234.622W/cm^2$

When the second is removed the third polarizer becomes the second and final polarizer so the intensity of light would be mathematically evaluated as

$I_f_3 = \frac{I_p}{2} cos ^2 \theta_2$

$I_f_3$ is the intensity of the light emerging from the stack

substituting values

$I_f_3 = \frac{234.622}{2} * cos^2(61)$

$I_f_3 = 27.57 W/cm^2$

When the third polarizer is removed the second polarizer becomes the

the final polarizer and the intensity of light emerging from the stack would be

$I_f_2 = \frac{I_p}{2} cos ^2 \theta_1$

$I_f_2$ is the intensity of the light emerging from the stack

Substituting values

$I_f_2 = \frac{234.622}{2} cos^2 (21)$

$I_f_2 = 102.24 W/cm^2$

7 0

2 years ago

PLEASE HELP ME I NEED IT!!

Alla [95]

Answer:

d

Explanation:

7 0

2 years ago

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Ponds and lakes are part of marine ecosystem. True or false ?

finlep [7]

Answer:

True

Explanation:

because they can hold marine organism inside

8 0

2 years ago

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Which statement is the best interpretation of the ray diagram shown below?

madreJ [45]

A) A concave mirror forming a larger, virtual image

Explanation:

The figure is missing; see attachment.

There are two types of mirror:

Concave (converging) mirrors: a concave mirror is a mirror that reflects the light inward
Convex (diverging) mirrors: a convex mirror is a mirror that reflects the light outward

The image formed by a mirror can also be of two types:

Real image: it is formed on the same side of the object, with respect to the mirror
Virtual image: it is formed on the opposite side of the object, with respect to the mirror

In the figure of this problem (see attachment), we see that:

- The mirror reflects the light from the object inward --> so it is a concave mirror

- The image is formed on the other side of the mirror --> it is a virtual image

So the correct option is

A) A concave mirror forming a larger, virtual image

Learn more about mirrors:

brainly.com/question/8737441

#LearnwithBrainly

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3 years ago

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