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Leokris [45]
3 years ago
6

Because the snow suddenly gets too slushy, you decide to carry your 100-n sled the rest of the way home. How much work do you do

when you pick up the sled, lifting it 0.5 m upward? how much work do you do to carry the sled if your if your house is 800 m away?
Physics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

 Work  =  (weight) x (distance lifted)

           =  (100 N)  x  (0.5 m)

           =       50 joules.


If you carry the sled level all the way to your house, you're not moving it
against gravity. 

Although you're huffing and puffing and sweating by the time you reach
your house, still, according to the Physics definition of work, you have
done NO work on the sled all the way home.
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loris [4]

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of options. However, one material that is good candidate for conducting electricity without reacting with other materials is metallic vanadium dioxide. This is because of the inability of this electrical conductor to conduct heat (an unusual property for all other electrical conductors) and thus makes it difficult for it to react with other materials (since an increase in temperature increases possibility of a reaction).

6 0
3 years ago
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Alja [10]

Given :

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.

The force of friction between the refrigerator and the floor is 230 N.

To Find :

How much work has been performed by the mover on the refrigerator.

Solution :

Since, refrigerator is moving with constant velocity.

So, force applied by the mover is also 230 N ( equal to force of friction ).

Now, work done in order to move the refrigerator is :

W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m

Hence, this is the required solution.

3 0
3 years ago
A spherical shell with a net charge of 3Q surrounds a point charge of -q at the center of the shell. The charges on the inner an
aleksley [76]

Answer:

1) The charge on the outer shell is +4·Q

2) The charge on the inner shell is +Q

Explanation:

1) The given parameters of the spherical shell are;

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The point charge surrounded by the spherical shell = -Q

Let 'x' represent the charge on the outer shell, and let 'y', represent the charge on the inner shell, we have;

The net charge, 3·Q = -q + x

∴ x = 3·Q + Q = 4·Q

The charge on the outer shell, x = 4·Q

2) The net charge in the shell is zero, therefore, the charge on the inner shell, 'y', is given as follows;

-Q + y = 0

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5 0
3 years ago
Two loudspeakers in a 20c room emit 686 hz sound waves along the x-axis.a. if the speakers are in phase, what is the smallest di
jeyben [28]

<u>Answer :</u>

(a) d = 0.25 m

(b) d = 0.5 m

<u>Explanation :</u>

It is given that,

Frequency of sound waves, f = 686 Hz

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(1) Perfectly destructive interference occurs when the path difference is half integral multiple of wavelength i.e.

d=\dfrac{\lambda}{2}........(1)

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v=f\times \lambda

d=\dfrac{v}{2f}

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4 0
3 years ago
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The Bohr's proposal for the angular momentum of an electron in Bohr's model of the hydrogen atom is:

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7 0
3 years ago
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