Speed = 52/1.57576= 33 m/s
Explanation:
Distance = speed * time
Given , the distance traveled by the baseball = 52 m
Speed of sound in air = 330 m/s
Total time = 1.73333 s .
Total time for the student to hear the sound of the gong is the sum of the time take for the baseball to reach the gong and the time taken by the sound to travel back.
Distance traveled by the sound is 52 m and the speed is 330 m/s
So time taken by the sound to travel back = distance traveled / the speed
=> time = 52/330 s = 0.15757 s
Time taken by the base ball to reach the gong is the total time - the time taken by the sound
=> time taken by base ball = 1.73333 - 0.15757 = 1.57576s
Speed of the base ball to reach the gong = distance / time
Speed = 52/1.57576= 33 m/s
Energy = power × time
1800 = 300 × time
time = 1800 ÷ 300 = 6 s
Hope it helped!
Answer:
During charging by conduction, both objects acquire the same type of charge. If a negative object is used to charge a neutral object, then both objects become charged negatively. ... In this case, electrons are transferred from the neutral object to the positively charged rod and the sphere becomes charged positively.
Answer:
<u>2.48 m</u> is the length of the rope.
Explanation:
Cycle period is 321
Time is 20 second
Wave travels at speeds = 26.4 m/s
We know that,

Frequency required for 321 complete cycle in 20 seconds is

Frequency = 16.05 hz
We know that,


λ = wavelength, the distance between "wave crests" (m)
v = wave velocity, the "speed" that waves are moving in a direction (m/s)
f = frequency, (cycles/ or Hz)

λ = 1.65 m
As per given question "length of the rope has three equal length segment"



Length of the rope = 2.48 m
Therefore, length of the rope is <u>2.48 m.</u>
Answer:
44200 N
Explanation:
To calculate the average force exerted on the car, we will use the following equation

Where F is the average force, t is the time, m is the mass, vf is the final velocity and vi is the initial velocity of the car.
Replacing t = 0.5s, m = 1300 kg, vf = -2 m/s, and vi = 15 m/s and solving for F, we get

Therefore, the average force exerted on the car by the wall was 44200 N