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seraphim [82]
3 years ago
7

A power plant burns coal to generate electricity. Suppose that 1000 J of heat (Q) from the coal fire enters a boiler, which is k

ept at a constant temperature of 900 C. That 1000 J is used to boil water in a boiler. The steam from the boiler is used to drive a turbine that creates electricity (work). The excess heat is put into a cooling tower at 5 C.
Carnot efficiency If everything is perfectly efficient,
• What is the maximum efficiency that the plant could operate at?
• How much work could be done starting from that 1000 J?
Physics
1 answer:
balandron [24]3 years ago
5 0

Answer:

The work done will be "763 J". A further explanation is given below.

Explanation:

The given values are:

Q_1=1000 \ J

Temperature,

T_1=900^{\circ} C

i.e,

    =1173

T_2=5^{\circ}C

i.e.,

    =278

As we know,

⇒  \eta =1-\frac{T_2}{T_1}

On substituting the values, we get

⇒     =1-\frac{278}{1173}

⇒     =\frac{1173-278}{1173}

⇒     =\frac{895}{1173}

⇒     =0.763

then,

⇒  W=\eta Q_1

⇒       =0.763\times 1000

⇒       =763 \ J

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(b) The velocity of the carrier is 0.40872 m/s.

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