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BlackZzzverrR [31]
3 years ago
14

1. Earth's ozone layer is responsible for absorbing from the sun

Physics
2 answers:
Olenka [21]3 years ago
6 0

Answer:

UV light

climate

hydrofluorocarbons or HFCs

pollutants

heat

As sunlight falls on Earth's surface, it heats up the surface. Infrared light is emitted from the surface and is absorbed in the atmosphere, where it is converted to heat. This heat remains trapped in the atmosphere, causing the temperature near the surface to increase.

Explanation:

ladessa [460]3 years ago
5 0

Answer:

UV light

climate

hydrofluorocarbons or HFCs

pollutants

heat

As sunlight falls on Earth's surface, it heats up the surface. Infrared light is emitted from the surface and is absorbed in the atmosphere, where it is converted to heat. This heat remains trapped in the atmosphere, causing the temperature near the surface to increase.

Explanation:

these are all correct

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When a substance absorbs or releases heat, the ______ changes.
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I’m pretty sure it’s kinetic energy
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Here is help for researching and writing your essay:

- choose one of the essay questions
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3 years ago
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For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is
ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)

where A(t)=A₀e^{\frac{-bt}{2m}}

 A₀ is the amplitude at t=0 and

w' is the angular frequency of damped SHM, which is given by,

w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

Now coming to the problem,

Given: m=1.2 kg

           k=9.8 N/m

           b=210 g/s= 0.21 kg/s

           A₀=13 cm

a) A(t)=A₀/8

⇒A₀e^{\frac{-bt}{2m}} =A₀/8

⇒e^{\frac{bt}{2m}}=8

applying logarithm on both sides

⇒\frac{bt}{2m}=ln(8)

⇒t=\frac{2m*ln(8)}{b}

substituting the values

t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)

b) w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}

T'=\frac{2\pi}{w'}, where T' is time period of damped SHM

⇒T'=\frac{2\pi}{2.86}=2.2s

let n be number of oscillations made

then, nT'=t

⇒n=\frac{24}{2.2}=11(approx)

8 0
4 years ago
What does the w mean in w=fxd
Volgvan

Answer:

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Explanation:

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A 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. the bullet emerges (the bullet does not get embedded in
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The velocity of the block after the collision is 1.5 m/s.
7 0
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