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3 years ago

5

You and your little cousin sit on a see-saw. You sit 0.5 m from the fulcrum, and your cousin sits 1.5 m from the fulcrum. You we

igh 600 N. How much does she weigh?

1 answer:

svetoff [14.1K]3 years ago

7 0

Answer:

200N

Explanation:

0.5/1.5=x/600N

1/3=x/600

x=200N

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A second order measuring system has a known natural frequency of 2000 Hz and damping ratio of 0.8. Would it be satisfactory to u

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Answer:

The expected dynamic error is 0.019

The phase shift is -23.10°C

Explanation:

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3 years ago

A trumpet creates a sound wave that has a wave speed of 350m/s and a wavelength of 0.8 m . What is the frequency of the sound wa

ValentinkaMS [17]

Answer:

The frequency of sound wave created by trumpet is 437.5Hz

Explanation:

Given

the speed of sound wave = 350 m $s^{-1}$

the wavelength of sound wave = 0.8 m

the frequency of sound wave = ?

All the waves have same relationship among wavelength, frequency and speed, which is given by the equation:

v = fλ, where

v is speed of the wave

f is frequency of the wave

λ is wavelength of the wave

therefore frequency of sound wave is given by

f = v/λ

= 350m $s^{-1}$ /0.8m

= 437.5 $s^{-1}$

= 437.5Hz (since 1 $s^{-1}$ = 1 Hz (Hertz)

Hence the frequency of sound wave created by trumpet is 437.5Hz

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3 years ago

The picture shows a loop of wire rotating in a magnetic field in a generator. Determine the direction of the current through the

BaLLatris [955]

I believe the answer is b

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3 years ago

Read 2 more answers

A piano wire with mass 2.95 g and length 79.0 cm is stretched with a tension of 29.0 N . A wave with frequency 105 Hz and amplit

Romashka-Z-Leto [24]

The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as

$P = \frac{1}{2} \mu \omega^2 A^2 v$

Here,

$\mu$ = Linear mass density of the string

$\omega =$ Angular frequency of the wave on the string

A = Amplitude of the wave

v = Speed of the wave

At the same time each of this terms have its own definition, i.e,

$v = \sqrt{\frac{T}{\mu}} \rightarrow$ Here T is the Period

For the linear mass density we have that

$\mu = \frac{m}{l}$

And the angular frequency can be written as

$\omega = 2\pi f$

Replacing this terms and the first equation we have that

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2(\sqrt{\frac{T}{\mu}})$

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2 (\sqrt{\frac{T}{m/l}})$

$P = 2\pi^2 f^2A^2(\sqrt{T(m/l)})$

PART A ) Replacing our values here we have that

$P = 2\pi^2 (105)^2(1.8*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.2320W$

PART B) The new amplitude A' that is half ot the wavelength of the wave is

$A' = \frac{1.8*10^{-3}}{2}$

$A' = 0.9*10^{-3}$

Replacing at the equation of power we have that

$P = 2\pi^2 (105)^2(0.9*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.058W$

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3 years ago

Using the criteria you described in your previous answer, how would you compare solar power to fossil fuel power?

Scilla [17]

Solar power differ to fossil fuel power in that solar power is a much more optimal resource than fossil fuels

Solar power; however provides much more energy than fossil fuel power
Interestingly too, solar power resource can be used without releasing greenhouse gases compared to fossil fuels power
Infact, solar energy is the most reliable

<h3>What is renewable energy?</h3>

Renewable energy simply refers to energy that is not depleted when used. An example of such is solar power.

So therefore, solar power differ to fossil fuel power in that solar power is a much more optimal resource than fossil fuels

Learn more about renewable energy:

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2 years ago