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2 years ago

5

You and your little cousin sit on a see-saw. You sit 0.5 m from the fulcrum, and your cousin sits 1.5 m from the fulcrum. You we

igh 600 N. How much does she weigh?

1 answer:

svetoff [14.1K]2 years ago

7 0

Answer:

200N

Explanation:

0.5/1.5=x/600N

1/3=x/600

x=200N

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a high schooler who lives on the "5th" floor of an apartment complex dropped his phone off the balcony. If the balcony is 18.75

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Answer:

1.38 s

Explanation:

Use the free falling formula

T = √(L)/ g

T = √18.75/9.8

T = 1.38 s

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2 years ago

Light is an electromagnetic wave and travels at a speed of 3.00 × 108 m/s. The human eye is most sensitive to yellow-green light

Nimfa-mama [501]

Answer:

$f = 5.95 \times 10^{14} Hz$

Explanation:

As we know that the frequency of the wave is given as

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here we know that

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2 years ago

. The p.d. at the terminals of a battery is 25V when no load is connected and 24V when a load taking 10A is connected. Determine

makvit [3.9K]

Answer:

the internal resistance of the cell is 0.1 ohm.

Explanation:

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p.d at the terminals of a battery at a load, E₂ = 24 V

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3 years ago

Please send help my way. 10 points to the brainliest

antoniya [11.8K]

The possible units for impulse would be:
<span>(N. s)
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3 years ago

A 55-kg block, starting from rest, is pushed a distance of 5.0 m across a floor by a horizontal force Fp whose magnitude is 140

max2010maxim [7]

Answer:

The answer is "151.25 J and -547.64 J".

Explanation:

$u = 0\\\\v = 2.35\ \frac{m}{sec}\\\\d = 5.0 \ m\\\\$

Using formula:

$v^2 = u^2 + 2 \times a \times d\\\\2.35^2 = 0^2 + 2 \times a \times 5\\\\a = \frac{2.35^2}{10} \\\\$

$= 0.55 \ \frac{m}{sec^2}\\\\$

$F_{net} = m \times a\\\\F_{net} = 55 \times 0.55 = 30.25\ N\\\\$

Calculating the Work by net force

$W = F_{net}\times d\\\\W = 30.25 \times 5 = 151.25 \ J\\\\$

The above work is converted into thermal energy.

Now,

$F_{net} = F_p - F_f\\\\F_p = 140 \ N\\\\F_f = u_k\times m \times g = u_k \times 55 \times 9.81\\\\F_f = 539.55 \times u_k\\\\30.25 = 140 - u_k \times 55 \times 9.81\\\\u_k = \frac{(140 - 30.25)}{(55\times 9.81)}\\\\uk = 0.203 = \text{Coefficient of friction}\\\\W_f = -F_f \times d\\\\W_f = -0.203 \times 55 \times 9.81 \times 5\\\\Work\ done\ by\ friction = -547.64 \ J$

6 0

2 years ago