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anastassius [24]
3 years ago
13

During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t2 to so

lve your answer. (Do not forget to keep units in your answer.)
Physics
1 answer:
Alexus [3.1K]3 years ago
5 0

I think the formula should be x=1/2at^2. This means the answer would be 70560m
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4 0
3 years ago
Read 2 more answers
Four identical particles of mass 0.514 kg each are placed at the vertices of a 4.70 m x 4.70 m square and held there by four mas
Alona [7]

In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.

Our values are given by:

m = 0.514kg

I = 4.7m (each side)

A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,

I = 4m (\frac{l}{2})^2\\I = 4*(0.514)(\frac{4.7}{2})^2\\I =  11.35kgm^2\\

B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,

I = 2m(\frac{l}{2})^2+2m(\frac{l}{2}^2+l^2)\\I = 2*(0.514)*(\frac{4.7}{2})^2+2*(0.514)*((\frac{4.7}{2})^2+4.7^2)\\I = 34.06Kgm^2

C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,

I = \frac{1}{2}*l^2

I = \frac{1}{2}*(4.7)^2

I = 11.045kgm^2

7 0
3 years ago
Select all that apply so it’s not just one answer. please and thanks :))
qwelly [4]
Using sources that are peer reviewed
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boyakko [2]
The correct answer is
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In fact, the friction force between the road and the tires of the car acts as centripetal force, keeping the car in circular motion.</span>
5 0
3 years ago
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